Pyspark udf 在 Python 函数有效时不起作用

Question

我有一个Python函数：

def get_log_probability(string, transition_log_probabilities):
    string = ngrams(string, 2)
    terms = [transition_log_probabilities[bigram]
                       for bigram in string]
    log_probability = sum(terms)/len(terms) if len(terms) > 0 else sum(terms)
    return log_probability

我想将此函数用于 Pyspark DataFrame 列，transition_log_probabilities 作为常量，如下所示：

transition_log_probabilities = {('a', 'a'): -3.688879454113936,
('a', 'b'): -3.688879454113936,
('a', 'c'): -3.688879454113936,
('b', 'a'): -3.688879454113936,
('b', 'b'): -3.688879454113936,
('b', 'c'): -3.688879454113936,
('c', 'a'): -3.688879454113936,
('c', 'b'): -3.688879454113936,
('c', 'c'): -3.688879454113936}

所以我将其更改为 Pyspark UDF：

def get_log_prob_udf(dictionary):
    return udf(lambda string: get_log_probability(string, dictionary), FloatType())

即使 get_log_probability("abc", transition_log_probabilities) 有效并给出了 -3.688879454113936 的结果，当我将其 UDF 应用到 Pyspark 时如下所示：

df = df \
.withColumn("string_log_probability", get_log_prob_udf(transition_log_probabilities)(col('string')))

不行，抛出

的错误

An error occurred while calling o3463.showString.
: org.apache.spark.SparkException: Job aborted due to stage failure: Task 0 in stage 
182.0 failed 1 times, most recent failure: Lost task 0.0 in stage 182.0 (TID 774) 
(kubernetes.docker.internal executor driver): net.razorvine.pickle.PickleException: 
expected zero arguments for construction of ClassDict (for numpy.dtype)

有谁知道怎么解决吗？非常感谢。

Answer 1

希望这就是您要寻找的结果。

df = spark.createDataFrame( [ (1, "bc"), (2, "aa"), (3, "ca") ], ["id", "string"] )
                           
from pyspark.sql import functions as F, types as T
from nltk import ngrams
                           
transition_log_probabilities = {('a', 'a'): -3.688879454113936,
        ('a', 'b'): -3.688879454113936,
        ('a', 'c'): -3.688879454113936,
        ('b', 'a'): -3.688879454113936,
        ('b', 'b'): -3.688879454113936,
        ('b', 'c'): -3.688879454113936,
        ('c', 'a'): -3.688879454113936,
        ('c', 'b'): -3.688879454113936,
        ('c', 'c'): -3.688879454113936}
    
def get_log_probability(string):
    
    string = ngrams(string, 2)
    terms = [transition_log_probabilities[bigram]
                       for bigram in string]
    log_probability = sum(terms)/len(terms) if len(terms) > 0 else sum(terms)
    return log_probability


get_log_prob_udf = udf(get_log_probability, T.FloatType())

df = df.withColumn('string_log_probability', get_log_prob_udf(F.col('string'))).show()

+---+------+----------------------+
| id|string|string_log_probability|
+---+------+----------------------+
|  1|    bc|            -3.6888795|
|  2|    aa|            -3.6888795|
|  3|    ca|            -3.6888795|
+---+------+----------------------+

Pyspark udf 在 Python 函数有效时不起作用

Pyspark udf doesn't work while Python function works

python

pyspark