通过 SQL 服务器 table 循环创建 json RUBY
Creating json with RUBY looping through SQL Server table
这是这个问题的后续:
我能够在 JSON 中创建嵌套数组。但是我正在努力循环遍历记录并为每条记录附加一个文件。另外,我将如何在 json 的顶部而不是在每条记录上添加根元素。 “aSequences”只需要在顶部一次...我还需要在每条记录之间使用逗号。
到目前为止,这是我的代码
require 'pp'
require 'tiny_tds'
require 'awesome_print'
require 'json'
class Document
def initialize strategy
@document = strategy
#load helper functions
load "helpers_ruby.rb"
#set environment 'dev', 'qa', or 'production'
load "envconfig_ruby.rb"
end
def StartUP
@document.StartUP
end
def getseqrecord
@document.getseqrecord
end
end
class GetSqlaaSequence
def StartUP
##system "clear" ##linux
system "cls" ##Windows
# create connection to db
$connReportingDB = createReportingxxSqlConn($ms_sql_host, $ms_sql_user, $ms_sql_password, $ms_sql_dbname)
##$currentDateTime = DateTime.now
##pp 'def StartUP ran at: '+$currentDateTime.to_s
end
def getseqrecord
# get the aaaaSequences data
@result = $connReportingDB.execute("SELECT
[jsonFile]
,[id]
,[title]
,[authorIds]
,[name]
,[aminoAcids]
,[schemaId]
,[registryId]
,[namingStrategy]
FROM tablename
")
$aaSequences = Array.new
@i = 0
@result.each do |aaSequence|
jsonFile = aaSequence['jsonFile']
id = aaSequence['id']
title = aaSequence['title']
authorIds = aaSequence['authorIds']
name = aaSequence['name']
aminoAcids = aaSequence['aminoAcids']
schemaId = aaSequence['schemaId']
registryId = aaSequence['registryId']
namingStrategy = aaSequence['namingStrategy']
##end
@hash = Hash[
"jsonFile", jsonFile,
"id", id,
"title", title,
"authorIds", authorIds,
"name", name,
"aminoAcids", aminoAcids,
"schemaId", schemaId,
"registryId", registryId,
"namingStrategy", namingStrategy
]
@filename = jsonFile
jsonFileOutput0 = {:"#{title}" => [{:authorIds => ["#{authorIds}"],:aminoAcids => "#{aminoAcids}",:name => "#{name}",:schemaId => "#{schemaId}",:registryId => "#{registryId}",:namingStrategy => "#{namingStrategy}"}]}
jsonFileOutput = JSON.pretty_generate(jsonFileOutput0)
File.open(jsonFile,"a") do |f|
f.write(jsonFileOutput)
####ad the comma between records...Not sure if this is the best way to do it...
# File.open(jsonFile,"a") do |f|
# f.write(',')
# end
end
$aaSequences[@i] = @hash
@i = @i + 1
##@createReportingSqlConn.close
end
end
end
Document.new(GetSqlaaSequence.new).StartUP
#get aaSequences and create json files
Document.new(GetSqlaaSequence.new).getseqrecord
这是迄今为止创建的 json 示例...
{
"aaSequences": [
{
"authorIds": [
"fff_fdfdfdfd"
],
"aminoAcids": "aminoAcids_data",
"name": "fdfdfddf-555_1",
"schemaId": "5555fdfd5",
"registryId": "5fdfdfdf",
"namingStrategy": "NEW_IDS"
}
]
}{
"aaSequences": [
{
"authorIds": [
"fff_fdfdfdfd"
],
"aminoAcids": "aminoAcids_data",
"name": "fdfdfddf-555_2",
"schemaId": "5555fdfd5",
"registryId": "5fdfdfdf",
"namingStrategy": "NEW_IDS"
}
]
}
这是我需要的示例
{
"aaSequences": [
{
"authorIds": [
"authorIds_data"
],
"aminoAcids": "aminoAcids_data",
"name": "name_data",
"schemaId": "schemaId_data",
"registryId": "registryId_data",
"namingStrategy": "namingStrategy_data"
},
{
"authorIds": [
"authorIds_data"
],
"aminoAcids": "aminoAcids_data",
"name": "name_data",
"schemaId": "schemaId_data",
"registryId": "registryId_data",
"namingStrategy": "namingStrategy_data"
}
]
}
您可以使用 FOR JSON
在 SQL 中完成全部操作。
不幸的是,数组无法使用此方法。有很多技巧,但在您的情况下最简单的方法是使用 JSON_MODIFY
附加到 []
SELECT
authorIds = JSON_MODIFY('[]', 'append $', a.authorIds),
[aminoAcids],
[name],
[schemaId],
[registryId],
[namingStrategy]
FROM aaSequences a
FOR JSON PATH, ROOT('aaSequences');
这是这个问题的后续:
我能够在 JSON 中创建嵌套数组。但是我正在努力循环遍历记录并为每条记录附加一个文件。另外,我将如何在 json 的顶部而不是在每条记录上添加根元素。 “aSequences”只需要在顶部一次...我还需要在每条记录之间使用逗号。
到目前为止,这是我的代码
require 'pp'
require 'tiny_tds'
require 'awesome_print'
require 'json'
class Document
def initialize strategy
@document = strategy
#load helper functions
load "helpers_ruby.rb"
#set environment 'dev', 'qa', or 'production'
load "envconfig_ruby.rb"
end
def StartUP
@document.StartUP
end
def getseqrecord
@document.getseqrecord
end
end
class GetSqlaaSequence
def StartUP
##system "clear" ##linux
system "cls" ##Windows
# create connection to db
$connReportingDB = createReportingxxSqlConn($ms_sql_host, $ms_sql_user, $ms_sql_password, $ms_sql_dbname)
##$currentDateTime = DateTime.now
##pp 'def StartUP ran at: '+$currentDateTime.to_s
end
def getseqrecord
# get the aaaaSequences data
@result = $connReportingDB.execute("SELECT
[jsonFile]
,[id]
,[title]
,[authorIds]
,[name]
,[aminoAcids]
,[schemaId]
,[registryId]
,[namingStrategy]
FROM tablename
")
$aaSequences = Array.new
@i = 0
@result.each do |aaSequence|
jsonFile = aaSequence['jsonFile']
id = aaSequence['id']
title = aaSequence['title']
authorIds = aaSequence['authorIds']
name = aaSequence['name']
aminoAcids = aaSequence['aminoAcids']
schemaId = aaSequence['schemaId']
registryId = aaSequence['registryId']
namingStrategy = aaSequence['namingStrategy']
##end
@hash = Hash[
"jsonFile", jsonFile,
"id", id,
"title", title,
"authorIds", authorIds,
"name", name,
"aminoAcids", aminoAcids,
"schemaId", schemaId,
"registryId", registryId,
"namingStrategy", namingStrategy
]
@filename = jsonFile
jsonFileOutput0 = {:"#{title}" => [{:authorIds => ["#{authorIds}"],:aminoAcids => "#{aminoAcids}",:name => "#{name}",:schemaId => "#{schemaId}",:registryId => "#{registryId}",:namingStrategy => "#{namingStrategy}"}]}
jsonFileOutput = JSON.pretty_generate(jsonFileOutput0)
File.open(jsonFile,"a") do |f|
f.write(jsonFileOutput)
####ad the comma between records...Not sure if this is the best way to do it...
# File.open(jsonFile,"a") do |f|
# f.write(',')
# end
end
$aaSequences[@i] = @hash
@i = @i + 1
##@createReportingSqlConn.close
end
end
end
Document.new(GetSqlaaSequence.new).StartUP
#get aaSequences and create json files
Document.new(GetSqlaaSequence.new).getseqrecord
这是迄今为止创建的 json 示例...
{
"aaSequences": [
{
"authorIds": [
"fff_fdfdfdfd"
],
"aminoAcids": "aminoAcids_data",
"name": "fdfdfddf-555_1",
"schemaId": "5555fdfd5",
"registryId": "5fdfdfdf",
"namingStrategy": "NEW_IDS"
}
]
}{
"aaSequences": [
{
"authorIds": [
"fff_fdfdfdfd"
],
"aminoAcids": "aminoAcids_data",
"name": "fdfdfddf-555_2",
"schemaId": "5555fdfd5",
"registryId": "5fdfdfdf",
"namingStrategy": "NEW_IDS"
}
]
}
这是我需要的示例
{
"aaSequences": [
{
"authorIds": [
"authorIds_data"
],
"aminoAcids": "aminoAcids_data",
"name": "name_data",
"schemaId": "schemaId_data",
"registryId": "registryId_data",
"namingStrategy": "namingStrategy_data"
},
{
"authorIds": [
"authorIds_data"
],
"aminoAcids": "aminoAcids_data",
"name": "name_data",
"schemaId": "schemaId_data",
"registryId": "registryId_data",
"namingStrategy": "namingStrategy_data"
}
]
}
您可以使用 FOR JSON
在 SQL 中完成全部操作。
不幸的是,数组无法使用此方法。有很多技巧,但在您的情况下最简单的方法是使用 JSON_MODIFY
[]
SELECT
authorIds = JSON_MODIFY('[]', 'append $', a.authorIds),
[aminoAcids],
[name],
[schemaId],
[registryId],
[namingStrategy]
FROM aaSequences a
FOR JSON PATH, ROOT('aaSequences');