合并多个哈希数组,其中一个值在 Ruby 中匹配
Merge multiple array of hashes where a value matches in Ruby
我有 3 个包含多个哈希的数组,我正试图将它们转换成单个哈希数组,其中 key/value 匹配
a = [{"name"=>"aaa", "a"=>"1", "b"=>"2"}, {"name"=>"bbb", "a"=>"1", "b"=>"2"}]
b = [{"name"=>"aaa", "c"=>"1", "d"=>"2"}, {"name"=>"bbb", "c"=>"1", "d"=>"2"}]
c = [{"name"=>"aaa", "e"=>"1", "f"=>"2"}, {"name"=>"bbb", "e"=>"1", "f"=>"2"}]
获得
combined = [{"name"=>"aaa", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}, {"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}]
我想这就是你需要的。
hashes = [a, b, c]
result = hashes.inject([]) do |result, hash_array|
hash_array.each do |hash|
index = result.find_index{|item| item["name"] == hash["name"]}
if index
result[index] = result[index].merge(hash)
else
result << hash
end
end
result
end
这看起来更酷,应该也能解决你的问题:
a.zip(b,c).map{|vertical_array| e.inject({}) {|result, k| result.merge(k)} }
控制台:
2.5.1 :016 > a.zip(b,c).map{|e|e.inject({}){|result, k| result.merge(k)} }
=> [{"name"=>"aaa", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}, {"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}]
[a,b,c].transpose
.map { |arr| arr.reduce(&:merge) }
#=> [{"name"=>"aaa", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"},
{"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}]
如果不能保证 a
、b
和 c
的元素顺序,可以写成
[a,b,c].map { |arr| arr.sort_by { |h| h["name"] } }
.transpose
.map { |arr| arr.reduce(&:merge) }
或
(a+b+c).each_with_object({}) do |g,h|
h.update(g["name"]=>g) { |_,o,n| o.merge(n) }
end.values
后者使用的形式Hash#update (aka merge!
) that employs a block ({ |_,o,n| o.merge(n) }
) to determine the values of keys that are present in both hashes being merged. Note that here the receiver of Hash#values是
(a+b+c).each_with_object({}) do |g,h|
h.update(g["name"]=>g) { |_,o,n| o.merge(n) }
end
#=> {"aaa"=>{"name"=>"aaa", "a"=>"1", "b"=>"2", "c"=>"1",
# "d"=>"2", "e"=>"1", "f"=>"2"},
# "bbb"=>{"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1",
# "d"=>"2", "e"=>"1", "f"=>"2"}]
此计算还允许数据内容更加多样化。假设,例如:
a = [{"name"=>"aaa", "a"=>"1", "b"=>"2"}, {"name"=>"bbb", "a"=>"1", "b"=>"2"}]
b = [{"name"=>"bbb", "c"=>"1", "d"=>"2"}, {"name"=>"ccc", "c"=>"1", "d"=>"2"}]
c = [{"name"=>"ccc", "e"=>"1", "f"=>"2"}, {"name"=>"aaa", "e"=>"1", "f"=>"2"}]
然后
(a+b+c).each_with_object({}) do |g,h|
h.update(g["name"]=>g) { |_,o,n| o.merge(n) }
end
#=> {"aaa"=>{"name"=>"aaa", "a"=>"1", "b"=>"2", "e"=>"1", "f"=>"2"},
# "bbb"=>{"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2"},
# "ccc"=>{"name"=>"bbb", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}]
我有 3 个包含多个哈希的数组,我正试图将它们转换成单个哈希数组,其中 key/value 匹配
a = [{"name"=>"aaa", "a"=>"1", "b"=>"2"}, {"name"=>"bbb", "a"=>"1", "b"=>"2"}]
b = [{"name"=>"aaa", "c"=>"1", "d"=>"2"}, {"name"=>"bbb", "c"=>"1", "d"=>"2"}]
c = [{"name"=>"aaa", "e"=>"1", "f"=>"2"}, {"name"=>"bbb", "e"=>"1", "f"=>"2"}]
获得
combined = [{"name"=>"aaa", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}, {"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}]
我想这就是你需要的。
hashes = [a, b, c]
result = hashes.inject([]) do |result, hash_array|
hash_array.each do |hash|
index = result.find_index{|item| item["name"] == hash["name"]}
if index
result[index] = result[index].merge(hash)
else
result << hash
end
end
result
end
这看起来更酷,应该也能解决你的问题:
a.zip(b,c).map{|vertical_array| e.inject({}) {|result, k| result.merge(k)} }
控制台:
2.5.1 :016 > a.zip(b,c).map{|e|e.inject({}){|result, k| result.merge(k)} }
=> [{"name"=>"aaa", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}, {"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}]
[a,b,c].transpose
.map { |arr| arr.reduce(&:merge) }
#=> [{"name"=>"aaa", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"},
{"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}]
如果不能保证 a
、b
和 c
的元素顺序,可以写成
[a,b,c].map { |arr| arr.sort_by { |h| h["name"] } }
.transpose
.map { |arr| arr.reduce(&:merge) }
或
(a+b+c).each_with_object({}) do |g,h|
h.update(g["name"]=>g) { |_,o,n| o.merge(n) }
end.values
后者使用的形式Hash#update (aka merge!
) that employs a block ({ |_,o,n| o.merge(n) }
) to determine the values of keys that are present in both hashes being merged. Note that here the receiver of Hash#values是
(a+b+c).each_with_object({}) do |g,h|
h.update(g["name"]=>g) { |_,o,n| o.merge(n) }
end
#=> {"aaa"=>{"name"=>"aaa", "a"=>"1", "b"=>"2", "c"=>"1",
# "d"=>"2", "e"=>"1", "f"=>"2"},
# "bbb"=>{"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1",
# "d"=>"2", "e"=>"1", "f"=>"2"}]
此计算还允许数据内容更加多样化。假设,例如:
a = [{"name"=>"aaa", "a"=>"1", "b"=>"2"}, {"name"=>"bbb", "a"=>"1", "b"=>"2"}]
b = [{"name"=>"bbb", "c"=>"1", "d"=>"2"}, {"name"=>"ccc", "c"=>"1", "d"=>"2"}]
c = [{"name"=>"ccc", "e"=>"1", "f"=>"2"}, {"name"=>"aaa", "e"=>"1", "f"=>"2"}]
然后
(a+b+c).each_with_object({}) do |g,h|
h.update(g["name"]=>g) { |_,o,n| o.merge(n) }
end
#=> {"aaa"=>{"name"=>"aaa", "a"=>"1", "b"=>"2", "e"=>"1", "f"=>"2"},
# "bbb"=>{"name"=>"bbb", "a"=>"1", "b"=>"2", "c"=>"1", "d"=>"2"},
# "ccc"=>{"name"=>"bbb", "c"=>"1", "d"=>"2", "e"=>"1", "f"=>"2"}]