为什么 elif 语句优先于我的 if 语句？

Question

所以我有一个数字猜谜游戏，我以前的所有代码都运行良好，您可能会看到我在屏幕上打印了随机生成的数字。但是当我猜对数字时，我仍然被告知我错了？

num = randrange(0, 100)

if num > 0 and num < 50:

print("The number is greater than 0 but smaller than 50")

elif num > 50 and num < 100:

print("The number is smaller than 100 but greater than 50")

print(num)

print('Start Guessing')

a = input()


a = input()
if a == num:

print ("You got the correct number, woohoo")

elif num > 0 and num < 20:

print ("Hint: The number is bigger than 0 but smaller than 20")

elif num > 20 and num < 40:

print ('Hint: The number is bigger than 20 but smaller than 40')

elif num > 40 and num < 60:

print ('Hint: The number is bigger than 40 but smaller than 60')

elif num > 60 and num < 80:

print ('Hint: The number is bigger than 60 but smaller than 80')

elif num > 80 and num < 100:

print ('Hint: The number is bigger than 80 but smaller than 100')

抱歉代码看起来很奇怪，我以前从未使用过这个网站。

Answer 1

您的代码似乎是 Python。您应该在标签中指出这一点。此外，由于 Python if 语句依赖于缩进，因此您应该 post 您的代码具有适当的缩进。

代码中：

a = input()
if a == num:

您正在将字符串与数字进行比较。您应该将 a 转换为 int.

if int(a) == num:

为什么 elif 语句优先于我的 if 语句？

Why is the elif statement taking priority over my if statement?

if-statement