Oracle 数据库 SQL 查询失败

Question

SQL 查询有问题。

查询如下：

SELECT employee_id,
   last_name,
   first_name,
   TO_DATE('31-DEC-01') - hire_date as "days_with_company",
   salary*12 as "annual_salary",
   (CASE WHEN "days_with_company" < 720 THEN "annual_salary"*0.1
         WHEN "days_with_company" >= 720 AND "days_with_company" < 1440 THEN "annual_salary"*0.2
         ELSE "annual_salary"*0.3 END) as "bonus",
    ("annual_salary" + "bonus") as "total_compensation"
    FROM employees;

但我收到以下错误：

ORA-00904: "bonus": invalid identifier
00904. 00000 -  "%s: invalid identifier"
*Cause:    
*Action:
Error at Line: 9 Column: 28

当我查找 error 时，似乎我做错了什么！

请指教

Answer 1

"bonus" 是在您尝试使用它的同一个 SQ 语句中生成的。 ("annual_salary" + "奖金") 为 "total_compensation" 那是不允许的。下面将它分开成一个单独的select语句。

WITH
aset
AS
    (SELECT employee_id
          , last_name
          , first_name
          , TO_DATE ('31-DEC-01') - hire_date    AS "days_with_company"
          , salary * 12                          AS "annual_salary"
          , (CASE
                 WHEN "days_with_company" < 720
                 THEN
                     "annual_salary" * 0.1
                 WHEN "days_with_company" >= 720
                  AND "days_with_company" < 1440
                 THEN
                     "annual_salary" * 0.2
                 ELSE
                     "annual_salary" * 0.3
             END)                                AS "bonus"
       FROM employees)
SELECT aset.*, ("annual_salary" + "bonus") AS "total_compensation"
  FROM aset;

我会三思而后行，将所有列名称括在双引号中。只需使用 Oracle 的默认值即可。 Oracle 将不在双引号中的对象名称视为大写，而不考虑大小写。这很简单，直接，并且在混合大小写滑入时消除了很多痛苦。

Oracle 数据库 SQL 查询失败

Oracle DB SQL Query Failing

sql

oracle