根据多列获取重复行的索引列

Question

我需要从下面获取 ID 和人名 table，其中地址 1、地址 2、州、城市、国家/地区列对所有角色具有相同的数据。

ID	Name	Address1	Address2	State	City
1	AB	AB@123	AB@345	st1	ct1
2	AB	AB@123	AB@345	st1	ct1
3	CD	AB@123	AB@345	st1	ct1
4	EF	EF@123	AB@345	st1	ct1

我想要输出为

ID	Name
1	AB
3	CD

select ID, Name, count(*) from person group by address1,address2,city,state having count(*) > 1;

给出异常：不是按表达式分组。

请提出一个更好的方法来实现输出。

Answer 1

您可以使用解析函数：

SELECT ID, Name, Address1, Address2, State, City
FROM   (
  SELECT p.*,
         COUNT(DISTINCT Name) OVER (PARTITION BY Address1, Address2, State, City)
           AS cnt,
         ROW_NUMBER() OVER (
           PARTITION BY Address1, Address2, State, City, Name
           ORDER BY id
         ) AS rn
  FROM   person p
)
WHERE  cnt > 1
AND    rn = 1;

其中，对于示例数据：

CREATE TABLE person (ID, Name, Address1, Address2, State, City) AS
SELECT 1, 'AB', 'AB@123', 'AB@345', 'st1', 'ct1' FROM DUAL UNION ALL
SELECT 2, 'AB', 'AB@123', 'AB@345', 'st1', 'ct1' FROM DUAL UNION ALL
SELECT 3, 'CD', 'AB@123', 'AB@345', 'st1', 'ct1' FROM DUAL UNION ALL
SELECT 4, 'EF', 'EF@123', 'AB@345', 'st1', 'ct1' FROM DUAL;

输出：

ID NAME ADDRESS1 ADDRESS2 STATE CITY

1 AB AB@123 AB@345 st1 ct1

3 CD AB@123 AB@345 st1 ct1

db<>fiddle here

根据多列获取重复行的索引列

get index column of duplicate rows based on multiple columns

sql

oracle