Oracle SQL 从一列计算增长值

Question

我要计算

INCOME_growth = INCOME_YTD - Income_prv_Month

我试过滞后功能，自我加入我无法让它工作

示例（起点）table_employee_info:

| Date        |Employee_NO|INCOME_YTD  |Date_ID|
---           |---        |---         |---    |
| 1/31/2022   |1002       |50          |202230
| 2/28/2022   |1045       |80          |202260
| 3/31/2022   |F104       |40          |202290
| 1/31/2022   |1002       |30          |202230
| 2/28/2022   |1045       |90          |202260
| 3/31/2022   |F104       |100         |202290
| 1/31/2022   |1002       |65          |202230
| 2/28/2022   |1045       |60          |202260
| 3/31/2022   |F104       |200         |202290

期望的结果将如下所示：首先，我们需要按 Employee_NO 然后按日期订购。其次，计算新列 Income_prv_Month。三、计算另一列INCOME_growth.

| Date        |Employee_NO|INCOME_YTD  |Income_prv_Month|INCOME_growth|Date_ID|
---           |---        |---         |---             |---         |---   
| 1/31/2022   |1002       |50          |0               |50          |202230
| 1/31/2022   |1002       |30          |50              |-20         |202230
| 1/31/2022   |1002       |65          |30              |30          |202230
| 2/28/2022   |1045       |80          |0               |80          |202260
| 2/28/2022   |1045       |90          |80              |10          |202260
| 2/28/2022   |1045       |60          |90              |-30         |202260
| 3/31/2022   |F104       |40          |0               |40          |202290  
| 3/31/2022   |F104       |100         |40              |60          |202290
| 3/31/2022   |F104       |200         |100             |100         |202290

如有任何提示或帮助，我将不胜感激

提前致谢

Answer 1

我认为您可以尝试使用 LAG window 函数，但真正的问题是，如果有我们可以将列替换为下面的查询 [column which represnt your expect order] 部分

SELECT t1.*,
       LAG(INCOME_YTD,1,0) OVER(PARTITION BY Employee_NO ORDER BY date_ID ) Income_prv_Month,
       INCOME_YTD - LAG(INCOME_YTD,1,0) OVER(PARTITION BY Employee_NO ORDER BY date_ID ) INCOME_growth
FROM T t1

Oracle SQL 从一列计算增长值

Oracle SQL Calculate growth value from ONE column

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