如何将不区分大小写的字符串与 python 中的 2 个列表进行比较

Question

我需要将一个字符串与 2 个列表进行比较。我有以下列表：

labels = ['admin', 'Admin', 'staff', 'techAdmin', 'techadmin']
accessCodeList = ['0x000', '0xAaA']

字符串输入：

mystring1 = "admin 0x000"
mystring2 = "demo 0x000"
mystring3 = "techAdmin 0x00"
mystring4 = "tech 0xAaA"
mystring5 = "techAdmin 0xAaA"
mystring6 = "Staff 0x000"   #-- starts with Uppercase

输出：

mystring1 = "Found"
mystring2 = "Not Found"
mystring3 = "Not Found"
mystring4 = "Not Found"
mystring5 = "Found"
mystring6 = "Found"  #-- case insensitive search result

Answer 1

将您输入的字符串转换为小写，然后检查其他列表是否包含该单词。 :

labels = ['admin', 'staff', 'techadmin']
accessCodeList = ['0x000', '0xAaA']

mystring6 = "Staff 0x000" 
mystring6_split = mystring6.split()
mystring6_split[0] = mystring6_split[0].lower()

if mystring6_split[0] in labels and mystring6_split[1] in accessCodeList:
    print('Found')
else:
    print('Not Found')

Answer 2

尝试将 labels 和 access_codes 转换为一组 O(1) 查找时间：

>>> labels = ['admin', 'Admin', 'staff', 'techAdmin', 'techadmin']
>>> access_codes = ['0x000', '0xAaA']
>>> inputs = ['admin 0x000', 'demo 0x000', 'techAdmin 0x00', 'tech 0xAaA', 'techAdmin 0xAaA', 'Staff 0x000']
>>> labels = {l.lower() for l in labels}
>>> access_codes = set(access_codes)
>>> for s in inputs:
...     label, code = s.split()
...     if label.lower() in labels and code in access_codes:
...         print(f'{s}, Found')
...     else:
...         print(f'{s}, Not Found')
...
admin 0x000, Found
demo 0x000, Not Found
techAdmin 0x00, Not Found  # 0x00 != 0x000 I think this is a typo in your example?
tech 0xAaA, Not Found
techAdmin 0xAaA, Found
Staff 0x000, Found

Answer 3

使用casefold.

labels = ['admin', 'staff', 'techadmin']
accessCodeList = ['0x000', '0xAaA']

mystring1 = "admin 0x000"
mystring2 = "demo 0x000"
mystring3 = "techAdmin 0x00"
mystring4 = "tech 0xAaA"
mystring5 = "techAdmin 0xAaA"
mystring6 = "Staff 0x000"   #-- starts with Uppercase


label, access_code = mystring1.split()
print('Found' if label.casefold() in labels and access_code in accessCodeList else 'Not Found')

label, access_code = mystring2.split()
print('Found' if label.casefold() in labels and access_code in accessCodeList else 'Not Found')

label, access_code = mystring3.split()
print('Found' if label.casefold() in labels and access_code in accessCodeList else 'Not Found')

label, access_code = mystring4.split()
print('Found' if label.casefold() in labels and access_code in accessCodeList else 'Not Found')

label, access_code = mystring5.split()
print('Found' if label.casefold() in labels and access_code in accessCodeList else 'Not Found')

label, access_code = mystring6.split()
print('Found' if label.casefold() in labels and access_code in accessCodeList else 'Not Found')

并遵循 DRY 原则，您可以创建一个函数。

def find_in_str(mystr):
    label, access_code = mystr.split()
    return 'Found' if label.casefold() in labels and access_code in accessCodeList else 'Not Found'

print(find_in_str(mystring1))
print(find_in_str(mystring2))
print(find_in_str(mystring3))
print(find_in_str(mystring4))
print(find_in_str(mystring5))
print(find_in_str(mystring6))

如何将不区分大小写的字符串与 python 中的 2 个列表进行比较

How to compare a case insensitive string to 2 list in python

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