根据 Python 中的另一个列表名称创建空列表

Question

将作为名称的列表的格式为：

 print(my_list)

我得到：

[[1, 1], [1, 2], [1, 4], [2, 1], [2, 2], [2, 4], [3, 3], [3, 5], [3, 6], [4, 1], [4, 2], [4, 4], [5, 3], [5, 5], [5, 6], [6, 3], [6, 5], [6, 6]]

我想根据这对数字创建空列表，例如：

for i in my_list:
    'H'+i[0]+i[1] = []

所以我会得到这样的东西：

H11 = []
H12 = []
H14 = ...

Answer 1

你可以这样做：

for i in my_list:
    globals()['H'+i[0]+i[1]] = []

print(H11)
print(H12)
...

但这似乎是一个糟糕的设计，我认为至少你应该尝试找到另一种方法。

Answer 2

不鼓励您描述的动态变量赋值。见 How do I create variable variables?, mentioned in the comment by Pranav Hosangadi. Use a dictionary instead, and assign it using dictionary comprehension:

my_lst = [[1, 1], [1, 2], [1, 4], [2, 1], [2, 2], [2, 4], [3, 3],
          [3, 5], [3, 6], [4, 1], [4, 2], [4, 4], [5, 3], [5, 5],
          [5, 6], [6, 3], [6, 5], [6, 6]]

my_dct = { f"H{lst[0]}{lst[1]}": [] for lst in my_lst}

print(my_dct)
# {'H11': [], 'H12': [], 'H14': [], 'H21': [], 'H22': [], 'H24': [], 'H33': [], 'H35': [], 'H36': [], 'H41': [], 'H42': [], 'H44': [], 'H53': [], 'H55': [], 'H56': [], 'H63': [], 'H65': [], 'H66': []}

print(my_dct['H11'])
# []

print(my_dct['H12'])
# []

根据 Python 中的另一个列表名称创建空列表

Creating empty lists base on another list name in Python

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