/teacher/8/ 处的字段错误。无法将关键字 'teacher' 解析为字段。选项有：教室、教员、faculty_id、id、姓名

Question

当我试图显示我的视图时，我在我的 django 项目中遇到了错误。这个问题似乎与课程模型有关，但老实说我不知道从哪里开始。

我的老师模型：

class Teacher(models.Model):
    GENDER_MALE = 0
    GENDER_FEMALE = 1
    GENDER_CHOICES = [(GENDER_MALE, 'Male'), (GENDER_FEMALE, 'Female')]
    
    fname = models.TextField(max_length=20)
    lname = models.TextField(max_length=20)
    gender = models.IntegerField(choices=GENDER_CHOICES)
    phone = models.IntegerField(default=None, blank=True, null=True)
    email = models.TextField(max_length=30, default=None, blank=True, null=True)
    faculty = models.ForeignKey('Faculty', on_delete=models.CASCADE )
    
    def __str__(self):
        return self.lname + ' ' +  self.fname

我的课程模型：

class Course(models.Model):
    name = models.TextField(max_length=50)
    faculty = models.ForeignKey('Faculty', on_delete=models.CASCADE )
    def __str__(self):
        return f'{self.name}'

我的 Faculty 模型：

class Faculty(models.Model):
    name = models.TextField(max_length=30)
    def __str__(self):
        return f'{self.name}'

我的看法：

def teacher(request, teacher_id):
    teacher = get_object_or_404(Teacher, pk=teacher_id)
    faculties = Faculty.objects.filter(teacher=teacher)
    course = Course.objects.filter(teacher=teacher)
    classrooms = Classroom.objects.filter(teacher=teacher)
    students = Student.objects.filter(teacher=teacher)
    # students = []
    # for cls in classrooms:
    #     students.extend(Student.objects.filter(classroom=cls))
    return render(request, 'polls/teacher.html', {'teacher': teacher,'faculties': faculties, 'courses':course,'classrooms':classrooms, 'students':students})

当我运行网站时，它指出我认为要停止的代码 course = Course.objects.filter(teacher=teacher)

我的模板：

{% extends "polls/base.html" %}
{% block body %}
    <h2>{{ teacher.fname }} {{ teacher.lname }}</h2>

    <h3>Faculty</h3>

    {% if faculties %}
        {% for faculty in faculties %}
            <p><a href="{% url 'faculty' faculty.id %}">{{ faculty.name }}</a></p>
        {% endfor %}
    {% else %}
        <p> </p>
    {% endif %}

    <h3>Course</h3>
    {%if courses %}
        {% for course in courses %}
            <p><a href="{% url 'course' course.id %}">{{ course.name }}</a> </p>
        {% endfor %}
    {% else %}
        <p> </p>
    {% endif %}

    <h3>Class</h3>
    {% if classrooms %}
        {% for class in classrooms %}
            <p><a href="{% url 'classroom' class.id %}">{{ class.name }}</a> </p>
        {% endfor %}
    {% else %}
        <p> </p>
    {% endif %}

    <h3>Student</h3>    
    {% if students %}
        {% for student in students %}
            <p><a href="{% url 'student' student.id %}">{{ student.fname }} {{ student.lname }}</a></p>
        {% endfor %}
    {% else %}
        <p> </p>
    {% endif %}

{% endblock %}

Answer 1

发生这种情况是因为以下行：

course = Course.objects.filter(teacher=teacher)

Course 模型没有字段 teacher，因此您无法按它进行过滤。要修复它，有两种选择：

向 Course 添加字段：

teacher = models.ForeignKey(Teacher, on_delete=models.CASCADE)

然后向每个已经存在的 Course 添加一个 Teacher（或使其成为 null=True）。

或者您可以通过教师所属的 Faculty 筛选 Course，以获取所有拥有属于该教员的教师的课程：

courses = Course.objects.filter(faculty=teacher.faculty)

或者，使用 reverse foreign key lookup:

courses = teacher.faculty.course_set.all()

/teacher/8/ 处的字段错误。无法将关键字 'teacher' 解析为字段。选项有：教室、教员、faculty_id、id、姓名

FieldError at /teacher/8/. Cannot resolve keyword 'teacher' into field. Choices are: classroom, faculty, faculty_id, id, name

python

django