将具有嵌套数组(树)的 JSON 数组转换为平面 JSON 数组
Convert JSON array with nested arrays (tree) to flat JSON array
我有这个 JSON 数组树,它可以包含任意数量的嵌套数组:
const namesArrayTree = [
{
"name": "Peter"
},
{
"name": "folder1",
"isArray": true,
"namesArray": [
{
"name": "Paul"
},
{
"name": "folder2",
"isArray": true,
"namesArray": [
{
"name": "Mary"
},
{
"name": "John"
}
]
}
]
},
{
"name": "Mark"
}
]
我需要将其转换为仅包含名称的平面数组:
const namesArrayFlat = [ "Peter", "Paul", "Mary", "John", "Mark" ]
所以我正在使用这段代码进行转换:
const namesArrayTree = [
{
"name": "Peter"
},
{
"name": "folder1",
"isArray": true,
"namesArray": [
{
"name": "Paul"
},
{
"name": "folder2",
"isArray": true,
"namesArray": [
{
"name": "Mary"
},
{
"name": "John"
}
]
}
]
},
{
"name": "Mark"
}
] ;
function getNamesList(item) {
let name = item.name;
let isArray = item.isArray;
if (isArray) {
name = item.namesArray.map(getNamesList).join("\r\n");
}
return name;
}
const namesList = namesArrayTree.map(getNamesList).join("\r\n");
const namesArrayFlat = namesList.split("\r\n");
console.log(namesArrayFlat)
代码运行良好,但我想摆脱使用 join.("\r\n")
创建名称列表然后使用 split("\r\n")
.[=18= 转换为数组的额外步骤]
也就是说,我想通过删除以下内容来减少代码:
function getNamesList(item) {
let name = item.name;
let isArray = item.isArray;
if (isArray) {
/* remove code to join by "\r\n" */
name = item.namesArray.map(getNamesList)
}
return name;
}
/* remove code to create "namesList" constant and remove code to join by "\r\n") */
const namesArrayFlat = namesArrayTree.map(getNamesList)
console.log(namesArrayFlat)
(上面的代码还是returns树形嵌套数组结构)
关于如何摆脱额外代码的任何想法?还有任何关于如何改进代码的建议都将非常有用,谢谢!
function getNamesList(item) {
return item.isArray ? item.namesArray.map(getNamesList) : item.name
}
const names = namesArrayTree.map(getNamesList).flat(Infinity)
console.log(names)
您可以使用数组缩减器实现此目的,如下所示:
const namesArray = [
{
"name": "Peter"
},
{
"name": "folder1",
"isArray": true,
"namesArray": [
{
"name": "Paul"
},
{
"name": "folder2",
"isArray": true,
"namesArray": [
{
"name": "Mary"
},
{
"name": "John"
}
]
}
]
},
{
"name": "Mark"
}
] ;
function reduceNamesList(list, item) {
if (item.isArray) {
return item.namesArray.reduce(reduceNamesList, list);
}
list.push(item.name)
return list
}
const namesList = namesArray.reduce(reduceNamesList, [])
console.log(namesList)
我有这个 JSON 数组树,它可以包含任意数量的嵌套数组:
const namesArrayTree = [
{
"name": "Peter"
},
{
"name": "folder1",
"isArray": true,
"namesArray": [
{
"name": "Paul"
},
{
"name": "folder2",
"isArray": true,
"namesArray": [
{
"name": "Mary"
},
{
"name": "John"
}
]
}
]
},
{
"name": "Mark"
}
]
我需要将其转换为仅包含名称的平面数组:
const namesArrayFlat = [ "Peter", "Paul", "Mary", "John", "Mark" ]
所以我正在使用这段代码进行转换:
const namesArrayTree = [
{
"name": "Peter"
},
{
"name": "folder1",
"isArray": true,
"namesArray": [
{
"name": "Paul"
},
{
"name": "folder2",
"isArray": true,
"namesArray": [
{
"name": "Mary"
},
{
"name": "John"
}
]
}
]
},
{
"name": "Mark"
}
] ;
function getNamesList(item) {
let name = item.name;
let isArray = item.isArray;
if (isArray) {
name = item.namesArray.map(getNamesList).join("\r\n");
}
return name;
}
const namesList = namesArrayTree.map(getNamesList).join("\r\n");
const namesArrayFlat = namesList.split("\r\n");
console.log(namesArrayFlat)
代码运行良好,但我想摆脱使用 join.("\r\n")
创建名称列表然后使用 split("\r\n")
.[=18= 转换为数组的额外步骤]
也就是说,我想通过删除以下内容来减少代码:
function getNamesList(item) {
let name = item.name;
let isArray = item.isArray;
if (isArray) {
/* remove code to join by "\r\n" */
name = item.namesArray.map(getNamesList)
}
return name;
}
/* remove code to create "namesList" constant and remove code to join by "\r\n") */
const namesArrayFlat = namesArrayTree.map(getNamesList)
console.log(namesArrayFlat)
(上面的代码还是returns树形嵌套数组结构)
关于如何摆脱额外代码的任何想法?还有任何关于如何改进代码的建议都将非常有用,谢谢!
function getNamesList(item) {
return item.isArray ? item.namesArray.map(getNamesList) : item.name
}
const names = namesArrayTree.map(getNamesList).flat(Infinity)
console.log(names)
您可以使用数组缩减器实现此目的,如下所示:
const namesArray = [
{
"name": "Peter"
},
{
"name": "folder1",
"isArray": true,
"namesArray": [
{
"name": "Paul"
},
{
"name": "folder2",
"isArray": true,
"namesArray": [
{
"name": "Mary"
},
{
"name": "John"
}
]
}
]
},
{
"name": "Mark"
}
] ;
function reduceNamesList(list, item) {
if (item.isArray) {
return item.namesArray.reduce(reduceNamesList, list);
}
list.push(item.name)
return list
}
const namesList = namesArray.reduce(reduceNamesList, [])
console.log(namesList)