减去单个对象中的相同变量 javascript

Question

const token = [
  {"token":"d2r4Z62OTGiPyNmdHTUfny",
  "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e",
  "time":1652767811},
  {"token":"eDZxQu0FSWm72D2-T1md5X",
  "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e",
  "time":1652767811}]; // Try edit me
  const arr = [];
  for (var i=0; i<=token.length-1; i++)
  {
    const millis = Date.now();
    const time  = Math.floor(millis / 1000);
    if (token[i].time > time) {
      arr.push(token[i].token)
    }
   }
   console.log(arr);

这两个token变量是一样的，我想把它们区分开来，怎么办？示例输出：

const example = [
  "d2r4Z62OTGiPyNmdHTUfny",
  "eDZxQu0FSWm72D2-T1md5X",
  "dnl13twkQIqifdvaxp1t6e"
];
console.log(example);

Answer 1

根据您当前的逻辑，最简单的方法是您可以使用 includes 来检查 token 和 arr 结果。如果它在arr，我们不需要把它推到arr。

const token = [
  {"token":"d2r4Z62OTGiPyNmdHTUfny",
  "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e",
  "time":1652767811},
  {"token":"eDZxQu0FSWm72D2-T1md5X",
  "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e",
  "time":1652767811}];
  const arr = [];
  for (var i=0; i<=token.length-1; i++)
  {
    const millis = Date.now();
    const time  = Math.floor(millis / 1000);
    if (!arr.includes(token[i].token) && token[i].time > time) {
      arr.push(token[i].token)
    }
   }
   console.log(arr);

Answer 2

只需使用 Set，因为它不允许重复：

const tokens = [
  {"token":"d2r4Z62OTGiPyNmdHTUfny", "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e", "time":1652767811},
  {"token":"eDZxQu0FSWm72D2-T1md5X", "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e", "time":1652767811}
];

const now = Math.floor(Date.now() / 1000);
const result = new Set(
  tokens.filter(({ time }) => time > now).map(({ token }) => token)
);

console.log(...result);

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