php 使用 NOT 运算符评估条件

Question

我有 4 个销售办公室，一旦所有 4 个销售办公室都收到了 20 个销售线索，只有 4 号销售办公室应该收到当天剩余的销售线索。我需要一些帮助来创建条件以基本上检查销售办公室 1-4 是否每个都收到了 20 个潜在客户，然后显然按照解释继续前进

首先，我查询数据库以检查我的计数器（是的，我知道这可以更紧凑，而是在循环中完成）

$sales_office= 1;
$sql = $conn->prepare("SELECT LeadsReceivedToday FROM Lead_Counter WHERE SalesOffice=?");
$sql->execute([$sales_office]);
$result = $sql->fetch();
$sales_office1_count = $result['LeadsReceivedToday'];

$sales_office= 2;
$sql = $conn->prepare("SELECT LeadsReceivedToday FROM Lead_Counter WHERE SalesOffice=?");
$sql->execute([$sales_office]);
$result = $sql->fetch();
$sales_office2_count = $result['LeadsReceivedToday'];

$sales_office= 3;
$sql = $conn->prepare("SELECT LeadsReceivedToday FROM Lead_Counter WHERE SalesOffice=?");
$sql->execute([$sales_office]);
$result = $sql->fetch();
$sales_office3_count = $result['LeadsReceivedToday'];

$sales_office= 4;
$sql = $conn->prepare("SELECT LeadsReceivedToday FROM Lead_Counter WHERE SalesOffice=?");
$sql->execute([$sales_office]);
$result = $sql->fetch();
$sales_office4_count = $result['LeadsReceivedToday'];

当我执行这个逻辑时它没有按预期工作？一旦 sales_office = 1 达到 20 个潜在客户，它就会直接移动到销售办公室 4?

if ($sales_office1_count != 20 && $sales_office2_count != 20 && $sales_office3_count != 20)
{
    //distribute leads to sales office 1-4 in order of 1-4
    
}
else
{
   //only send leads to sales office no 4
}

Answer 1

您当前对所有办公室计数的逻辑检查您必须分别检查它们中的每一个。

if ($sales_office1_count < 20 || $sales_office2_count < 20 || $sales_office3_count < 20)
{
    //distribute leads to sales office 1-4 in order of 1-4
    
}
else
{
   //only send leads to sales office no 4
}

此外，您可以使用数组提高代码的可读性：

$officesLeadsCount = [1 => 0, 2 => 0, 3 => 0, 4 => 0];

foreach ($officesLeadsCount as $number => $value) {
  $sql = $conn->prepare("SELECT LeadsReceivedToday FROM Lead_Counter WHERE SalesOffice=?");
  $sql->execute([$number]);
  $result = $sql->fetch();
  $officesLeadsCount[$number] = $result['LeadsReceivedToday'];    
}


if ($officesLeadsCount[1] < 20 || $officesLeadsCount[2] < 20 || $officesLeadsCount[3] < 20)
{
    //distribute leads to sales office 1-4 in order of 1-4

}
else
{
   //only send leads to sales office no 4
}

php 使用 NOT 运算符评估条件

php evaluate condition using NOT operator

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