应用于时间序列数据的时间增量

Question

我需要在 5 分钟的时间范围内提前一小时生成此数据。我申请了

timeAhead = times[-1] + pd.Timedelta(1, unit='hour')  
timeAhead

这里的结果是最后一步： Timestamp('2022-04-26 15:57:00+0000', tz='UTC', freq='300S')

但是，我找不到生成 5 分钟范围的方法。目标结果在“2022-04-26 14:57:00+00:00”之后提前一小时开始，例如：'2022-04-26 15:02:00+00:00', '2022-04-26 15:07:00+00:00','2022-04-26 15:12:00+00:00'............'2022-04-26 15:57:00+00:00'!

DatetimeIndex(['2022-04-26 11:02:00+00:00', '2022-04-26 11:07:00+00:00',
                   '2022-04-26 11:12:00+00:00', '2022-04-26 11:17:00+00:00',
                   '2022-04-26 11:22:00+00:00', '2022-04-26 11:27:00+00:00',
                   '2022-04-26 11:32:00+00:00', '2022-04-26 11:37:00+00:00',
                   '2022-04-26 11:42:00+00:00', '2022-04-26 11:47:00+00:00',
                   '2022-04-26 11:52:00+00:00', '2022-04-26 11:57:00+00:00',
                   '2022-04-26 12:02:00+00:00', '2022-04-26 12:07:00+00:00',
                   '2022-04-26 12:12:00+00:00', '2022-04-26 12:17:00+00:00',
                   '2022-04-26 12:22:00+00:00', '2022-04-26 12:27:00+00:00',
                   '2022-04-26 12:32:00+00:00', '2022-04-26 12:37:00+00:00',
                   '2022-04-26 12:42:00+00:00', '2022-04-26 12:47:00+00:00',
                   '2022-04-26 12:52:00+00:00', '2022-04-26 12:57:00+00:00',
                   '2022-04-26 13:02:00+00:00', '2022-04-26 13:07:00+00:00',
                   '2022-04-26 13:12:00+00:00', '2022-04-26 13:17:00+00:00',
                   '2022-04-26 13:22:00+00:00', '2022-04-26 13:27:00+00:00',
                   '2022-04-26 13:32:00+00:00', '2022-04-26 13:37:00+00:00',
                   '2022-04-26 13:42:00+00:00', '2022-04-26 13:47:00+00:00',
                   '2022-04-26 13:52:00+00:00', '2022-04-26 13:57:00+00:00',
                   '2022-04-26 14:02:00+00:00', '2022-04-26 14:07:00+00:00',
                   '2022-04-26 14:12:00+00:00', '2022-04-26 14:17:00+00:00',
                   '2022-04-26 14:22:00+00:00', '2022-04-26 14:27:00+00:00',
                   '2022-04-26 14:32:00+00:00', '2022-04-26 14:37:00+00:00',
                   '2022-04-26 14:42:00+00:00', '2022-04-26 14:47:00+00:00',
                   '2022-04-26 14:52:00+00:00', '2022-04-26 14:57:00+00:00'],
                  dtype='datetime64[ns, UTC]', freq='300S')

Answer 1

这将在您提供的日期前 1 小时为您提供另一列。

data = {'Date' : ['2022-04-26 11:02:00+00:00', '2022-04-26 11:07:00+00:00',
                   '2022-04-26 11:12:00+00:00', '2022-04-26 11:17:00+00:00',
                   '2022-04-26 11:22:00+00:00', '2022-04-26 11:27:00+00:00',
                   '2022-04-26 11:32:00+00:00', '2022-04-26 11:37:00+00:00',
                   '2022-04-26 11:42:00+00:00', '2022-04-26 11:47:00+00:00',
                   '2022-04-26 11:52:00+00:00', '2022-04-26 11:57:00+00:00',
                   '2022-04-26 12:02:00+00:00', '2022-04-26 12:07:00+00:00',
                   '2022-04-26 12:12:00+00:00', '2022-04-26 12:17:00+00:00',
                   '2022-04-26 12:22:00+00:00', '2022-04-26 12:27:00+00:00',
                   '2022-04-26 12:32:00+00:00', '2022-04-26 12:37:00+00:00',
                   '2022-04-26 12:42:00+00:00', '2022-04-26 12:47:00+00:00',
                   '2022-04-26 12:52:00+00:00', '2022-04-26 12:57:00+00:00',
                   '2022-04-26 13:02:00+00:00', '2022-04-26 13:07:00+00:00',
                   '2022-04-26 13:12:00+00:00', '2022-04-26 13:17:00+00:00',
                   '2022-04-26 13:22:00+00:00', '2022-04-26 13:27:00+00:00',
                   '2022-04-26 13:32:00+00:00', '2022-04-26 13:37:00+00:00',
                   '2022-04-26 13:42:00+00:00', '2022-04-26 13:47:00+00:00',
                   '2022-04-26 13:52:00+00:00', '2022-04-26 13:57:00+00:00',
                   '2022-04-26 14:02:00+00:00', '2022-04-26 14:07:00+00:00',
                   '2022-04-26 14:12:00+00:00', '2022-04-26 14:17:00+00:00',
                   '2022-04-26 14:22:00+00:00', '2022-04-26 14:27:00+00:00',
                   '2022-04-26 14:32:00+00:00', '2022-04-26 14:37:00+00:00',
                   '2022-04-26 14:42:00+00:00', '2022-04-26 14:47:00+00:00',
                   '2022-04-26 14:52:00+00:00', '2022-04-26 14:57:00+00:00']}
df = pd.DataFrame(data)
df['Date'] = pd.to_datetime(df['Date'], infer_datetime_format=True)
df['Fast_Forward_One_Hour'] = df['Date'] + datetime.timedelta(hours = 1)
df

应用于时间序列数据的时间增量

Time delta applying to time series data

python

datetime