Javascript 显示多种可能性的特定值

Question

我有一个具有不同状态（红色、黄色、绿色和 None）的项目列表，这些项目被分配给特定的程序。我需要将分配给程序的最关键颜色分配给变量。如果至少有一个红色我需要显示红色（无论是否有其他黄色或绿色）如果最关键的是黄色我需要显示黄色，不管是否有绿色。如果只有绿色，我需要显示绿色。如果分配了 none，我需要显示 none。下面的代码对于其中的 3 个是可以的，我不知道如何准确地添加 None 到它。所有值都是字符串。

问候彼得

function getProjectStatusProgram(program){
var status = '';
var grPrgTask = new GlideRecord('project');
grPrgTask.addQuery('u_program', program);
grPrgTask.query();
while (grPrgTask.next()){
    if (grPrgTask.overall_health == 'red'){
        status = "red";
        break;
    } else if (grPrgTask.overall_health == 'yellow'){
        status = 'yellow';          
    }           
}
if(status =='red' || status =='yellow')
return status;
else
return 'green';

}

Answer 1

理论示例，因为我没有所有相关代码。

/***
Returns a string with following task status priority:
 1: "red": if atleast one task has status "red"
 2: "yellow": if atleast one task has status "yellow"
 3: "none": if atleast one task has status "none"
 4: "green": if no task has either status "red", "yellow" or "none"
**/
function getProjectStatusProgram(program){
    //REM: Set default status to "green" due to "If there are only greens I need to display Green"
    var status = 'green';

    var grPrgTask = new GlideRecord('project');
    grPrgTask.addQuery('u_program', program);
    grPrgTask.query();

    while(grPrgTask.next()){
        //REM: "If there is at least one red I need to display red( no matter if there are other yellows or greens)"
        if(grPrgTask.overall_health == 'red'){
            status = "red";
            break;
        };

        //REM: "If the most critical one is yellow I need to display Yellow, not matter if there are greens."
        if(grPrgTask.overall_health == 'yellow'){
            status = 'yellow'
        }
        //REM: If current status is still "green" and this tasks status is "none" -> "none"
        //REM: Since it is only "green" if all are "green"
        else if(status == 'green' && grPrgTask.overall_health == 'none'){
            status = 'none'
        }
    };

    //REM: Just return the status
    return status
}

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