仅设置成员路由时排除CRUD资源

Question

我已将 Dish 操作的路线嵌套在 Restaurants 的路线中。唯一的问题是我只需要基于成员的路由而不是标准的基于 CRUD 的操作。有没有一种方法可以将它们全部排除，而不必像这样完全写出每个资源：

resources :dishes, except: [:new, :create, :edit, :update, :show, :destroy] do
  ...
end

或

resources :dishes, only: [:like, :unlike, :dislike, :undislike] do
  ...
end

当前设置

  resources :restaurants do
    resources :dishes do
      member do
        put "like",      to: "dishes#like"
        put "unlike",    to: "dishes#unlike"
        put "dislike",   to: "dishes#dislike"
        put "undislike", to: "dishes#undislike"
      end
    end
  end

Answer 1

你可以这样做
resources :restaurants do resources :dishes, only: [] do member do put "like", to: "dishes#like" put "unlike", to: "dishes#unlike" put "dislike", to: "dishes#dislike" put "undislike", to: "dishes#undislike" end end end

Answer 2

:only 选项告诉 Rails 只创建指定的路由。现在，如果您将空数组传递给唯一选项，它将不会创建任何内容，因为它需要数组中的操作名称。

所以这会起作用

resources :dishes, only: [] do

参考：http://guides.rubyonrails.org/v3.2.9/routing.html（4.6限制创建的路由）

仅设置成员路由时排除CRUD资源

Excluding CRUD resources when only setting up member routes

rest

model-view-controller

resources

routes

ruby-on-rails