洗牌集合和无法理解如何翻译 NewGuid()

Question

我有以下查询

 var nrOfRetrievedDocs = new List<RetrievedDocs>().Count();
 _docs= RavenSession.Query<DocsToProcess>().Skip(nrOfRetrievedDocs)
          .OrderBy(x=>Guid.NewGuid()).Take(1024).ToList();

我正在

An exception of type 'System.InvalidOperationException' occurred in Raven.Client.Lightweight.dll but was not handled in user code

Additional information: Cannot understand how to translate NewGuid()

我想在随机位置随机播放集合和 select 1024 个对象。

为什么我会遇到这个 Cannot understand how to translate NewGuid() 以及如何克服这个问题，是否有更好（更快）的方法来 select 集合中的随机项目？

Answer 1

如果你想随机排序，你可以直接这样做，而不是像这样：

http://ravendb.net/docs/article-page/3.0/csharp/client-api/session/querying/how-to-customize-query#randomordering

List<Employee> results = session.Query<Employee>()
    .Customize(x => x.RandomOrdering())
    .Where(x => x.FirstName == "Robert")
    .ToList();

洗牌集合和无法理解如何翻译 NewGuid()

shuffling collection and Cannot understand how to translate NewGuid()

.net

c#

ravendb