在最后一个字符之后和另一个字符之前解析

Question

我有一个看起来像这样的数组：

array(7) [
  0 => "account_bad_rooms_view-1" (24)
  1 => "account_view-2" (14)
  2 => "admin_collector_view-5" (22)
  3 => "admin_collector_edit-5" (22)
  4 => "machine_service_item_edit-57" (28)
  5 => "money_view-58" (13)
  6 => "mu_edit-61" (10)
]

我需要获取仅包含 "edit" 或 "view" 的子字符串，因此我需要在最后一个下划线之后和破折号之前解析该字符串。到目前为止我有这个：

foreach ($permissionsArray as $selectId => $permissions) {

    preg_match('~_(.*?)-~', $permissions, $output);
    dump($output[1]);

}

适用于只有一个下划线的字符串，所以结果是：

"bad_rooms_view"
"view"
"collector_view"
"collector_edit"
"service_item_edit"
"view"
"edit"

我怎样才能用简单的方法做到这一点？

Answer 1

_([^_]*)-

你可以使用这个instead.This不允许另一个_。

Answer 2

您可以使用 preg_filter 函数获得输出，而无需使用任何循环：

$array=array("account_bad_rooms_view-1", "account_view-2", "admin_collector_view-5",
  "admin_collector_edit-5", "machine_service_item_edit-57", "money_view-58", "mu_edit-61");

$matches = preg_filter('/^.+?_([^-_]+)-.*$/', '', $array);

print_r($matches);

输出：

Array
(
    [0] => view
    [1] => view
    [2] => view
    [3] => edit
    [4] => edit
    [5] => view
    [6] => edit
)

在最后一个字符之后和另一个字符之前解析

Parse after last character and before another character

php

regex

parsing

substring