PHP isset 在 else 语句中获取问题错误

Question

我正在尝试获取它，所以 index.php?steamusr=username 被设置为 var，如果指定了 none，它只会显示 else 语句中指定的错误。

我已经尝试过是否为空和isset。我一直在尝试我能找到的每一种组合，但仍然一无所获。这是我当前的代码，底部是错误信息。谢谢！

<?php
if (isset($_GET['steamusr'])) {
    $user = $_GET['steamusr'];
    $myinv = 'http://steamcommunity.com/id/$user/inventory/json/295110/1/';
    $content2 = file_get_contents($myinv);
    $json2 = json_decode($content2, true);
    $imgurlbase = 'http://steamcommunity-a.akamaihd.net/economy/image/';

    foreach($json2['rgDescriptions'] as $i){
       $item = $i['market_name'];
       $icon = $i['icon_url'];
       $fetchdata = 'http://steamcommunity.com/market/priceoverview/?appid=295110&currency=1&market_hash_name=' . urlencode($item);
       $grab = file_get_contents($fetchdata);
       $id = json_decode($grab, true);
       echo '<img src="'. $imgurlbase . $icon . '/64fx64f">' . '<a class="btn btn-primary btn-lg" href="#" role="button">'.'<span class="badge">1</span> ' . $item .'</a>' . '<a class="btn btn-primary btn-lg" href="#" role="button">'.'Low</br>'. $id['lowest_price'].'</a>'.'<a class="btn btn-primary btn-lg" href="#" role="button">'.'Avg</br>'. $id['median_price'].'</a>'.'<br>';
     }
else {
    echo '<h1>No steam user set</h2>';
}
}
?>

这里是错误：

[Wed Aug 19 09:24:33.723604 2015] [:error] [pid 21378] [client 67.90.138.68:62702] PHP Parse error: syntax error, unexpected 'else' (T_ELSE) in /var/www/index.php on line 58

Answer 1

更改这部分代码：

foreach($json2['rgDescriptions'] as $i){
$item = $i['market_name'];
$icon = $i['icon_url'];
$fetchdata = 'http://steamcommunity.com/market/priceoverview/?appid=295110&currency=1&market_hash_name=' . urlencode($item);
$grab = file_get_contents($fetchdata);
$id = json_decode($grab, true);
echo '<img src="'. $imgurlbase . $icon . '/64fx64f">' . '<a class="btn btn-primary btn-lg" href="#" role="button">'.'<span class="badge">1</span> ' . $item .'</a>' . '<a class="btn btn-primary btn-lg" href="#" role="button">'.'Low</br>'. $id['lowest_price'].'</a>'.'<a class="btn btn-primary btn-lg" href="#" role="button">'.'Avg</br>'. $id['median_price'].'</a>'.'<br>';
  }
  else {
echo '<h1>No steam user set</h2>';
  }
}

至

foreach($json2['rgDescriptions'] as $i){
    $item = $i['market_name'];
    $icon = $i['icon_url'];
    $fetchdata = 'http://steamcommunity.com/market/priceoverview/?appid=295110&currency=1&market_hash_name=' . urlencode($item);
    $grab = file_get_contents($fetchdata);
    $id = json_decode($grab, true);
    echo '<img src="'. $imgurlbase . $icon . '/64fx64f">' . '<a class="btn btn-primary btn-lg" href="#" role="button">'.'<span class="badge">1</span> ' . $item .'</a>' . '<a class="btn btn-primary btn-lg" href="#" role="button">'.'Low</br>'. $id['lowest_price'].'</a>'.'<a class="btn btn-primary btn-lg" href="#" role="button">'.'Avg</br>'. $id['median_price'].'</a>'.'<br>';
  }
}
else {
    echo '<h1>No steam user set</h2>';
  }

现在您将 else 放在 foreach 之后，而不是 if。

Answer 2

else 部分与您的第一个条件语句一起使用，因此需要将其放在最后一个大括号之后。

<?php
if (isset($_GET['steamusr'])) {
    $user = $_GET['steamusr'];
    $myinv = 'http://steamcommunity.com/id/$user/inventory/json/295110/1/';
    $content2 = file_get_contents($myinv);
    $json2 = json_decode($content2, true);
    $imgurlbase = 'http://steamcommunity-a.akamaihd.net/economy/image/';

    foreach($json2['rgDescriptions'] as $i){
        $item = $i['market_name'];
        $icon = $i['icon_url'];
        $fetchdata = 'http://steamcommunity.com/market/priceoverview/?appid=295110&currency=1&market_hash_name=' . urlencode($item);
        $grab = file_get_contents($fetchdata);
        $id = json_decode($grab, true);
        echo '<img src="'. $imgurlbase . $icon . '/64fx64f">' . '<a class="btn btn-primary btn-lg" href="#" role="button">'.'<span class="badge">1</span> ' . $item .'</a>' . '<a class="btn btn-primary btn-lg" href="#" role="button">'.'Low</br>'. $id['lowest_price'].'</a>'.'<a class="btn btn-primary btn-lg" href="#" role="button">'.'Avg</br>'. $id['median_price'].'</a>'.'<br>';
     }

  // else was here before

} else {
    echo '<h1>No steam user set</h2>';
}

?>

PHP isset 在 else 语句中获取问题错误

PHP isset get issue error in else statement

php

isset