如何让它在 "b" 之后改变字符

Question

我正在尝试制作一个蛮力类型的程序，但它变得太多 "b" 然后只是循环 "b"，我有点知道哪里出了问题，但不知道如何解决它这是我当前的代码

target = input("What is the target word for you to get?\n")

chars = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "0", "1", "2", "3", "3", "4", "5", "6", "7", "8", "9"]
currPos = int()

attempt = chars[currPos]
nxt = currPos + 1

while(attempt != target):
    print (attempt)
    attempt = chars[nxt]
    currPos += 1
    currPos = int(0)

print("Success! \""+ attempt + "\" was the correct password correct!")

我知道我将不得不将 while 循环更改为可能是 for 循环，甚至可能包含 while 循环。我不确定

Answer 1

currPos = int(0) 不正确。用

替换循环更简单

for attempt in chars :
    print(attempt)

如何让它在 "b" 之后改变字符

How to make it change char after "b"

python-3.x