更新具有相同 ID 的多行
UPDATE multiple rows with the same id
我正在开发 MaNGOS 数据库。目前我有自己的 id，但我想使用官方一次。问题是我的数据库中已经有一些我想更新的值。
我要更新的table是这样的
mysql> SELECT * FROM `character` LIMIT 10;
+----+---------------------------------+--------------+--------------+-------+
| id | char_name_de | char_name_en | id_new | id_old|
+----+---------------------------------+--------------+--------------+-------+
| 1 | | NULL | 2 | NULL |
| 2 | Abgesandter des Schattenhammers | NULL | 18201 | NULL |
| 3 | Abgesplittertes Skelett | NULL | 10478 | NULL |
| 4 | Adept aus Scholomance | NULL | 10469 | NULL |
| 5 | Aduscha | NULL | 18204 | NULL |
| 6 | Aggressiver Bluthund | NULL | 8922 | NULL |
| 7 | Akolyt aus Scholomance | NULL | 10471 | NULL |
| 8 | Akolyt der Schmetterschilde | NULL | 9045 | NULL |
| 9 | Althena | NULL | 18208 | NULL |
| 10 | Amadelis | NULL | 18209 | NULL |
+----+---------------------------------+--------------+--------------+-------+
10 rows in set (0.00 sec)
我正在尝试做的事情：
将 "id" 替换为 "new_id"
问题：
"id_new" 不是某些多语言字符串的唯一原因。 我想匹配成一行，把"id"存到"id_old"，把"id"换成"id_new"删除"id_new".
看起来像这样：
mysql> SELECT *
-> FROM `character`
-> WHERE id_new IN(
-> SELECT id_new
-> FROM `character`
-> GROUP BY `character`.id_new
-> HAVING COUNT(`character`.id_new) > 1
-> )
-> ORDER BY id_new ASC;
+-----+--------------------------+--------------+--------------+-------+
| id | char_name_de | char_name_en | id_new | id_old|
+-----+--------------------------+--------------+--------------+-------+
| 258 | Natter | NULL | 2914 | NULL |
| 342 | Snake | NULL | 2914 | NULL |
| 290 | Rat | NULL | 4075 | NULL |
| 292 | Ratte | NULL | 4075 | NULL |
| 276 | Orakel der Hakkari | NULL | 11346 | NULL |
| 152 | Hakkari Oracle | NULL | 11346 | NULL |
| 148 | Gurubashi Warrior | NULL | 11355 | NULL |
| 201 | Krieger der Gurubashi | NULL | 11355 | NULL |
| 344 | Sohn von Hakkar | NULL | 11357 | NULL |
| 347 | Son of Hakkar | NULL | 11357 | NULL |
| 47 | Bloodseeker Bat | NULL | 11368 | NULL |
| 51 | Blutsucherfledermaus | NULL | 11368 | NULL |
| 560 | Molten Giant | NULL | 11658 | NULL |
| 123 | Geschmolzener Riese | NULL | 11658 | NULL |
| 545 | Flamewaker | NULL | 11661 | NULL |
| 93 | Feuerschuppe | NULL | 11661 | NULL |
| 546 | Flamewaker Priest | NULL | 11662 | NULL |
| 94 | Feuerschuppenpriester | NULL | 11662 | NULL |
| 553 | Lava Annihilator | NULL | 11665 | NULL |
| 214 | Lavavernichter | NULL | 11665 | NULL |
| 540 | Firelord | NULL | 11668 | NULL |
| 92 | Feuerlord | NULL | 11668 | NULL |
| 543 | Flame Imp | NULL | 11669 | NULL |
| 104 | Flammenwichtel | NULL | 11669 | NULL |
| 536 | Core Hound | NULL | 11671 | NULL |
| 194 | Kernhund | NULL | 11671 | NULL |
| 534 | Ancient Core Hound | NULL | 11673 | NULL |
| 384 | Uralter Kernhund | NULL | 11673 | NULL |
| 549 | Golemagg the Incinerator | NULL | 11988 | NULL |
| 129 | Golemagg der Verbrenner | NULL | 11988 | NULL |
| 558 | Majordomo Executus | NULL | 12018 | NULL |
| 240 | Majordomus Exekutus | NULL | 12018 | NULL |
| 554 | Lava Elemental | NULL | 12076 | NULL |
| 212 | Lavaelementar | NULL | 12076 | NULL |
| 564 | Sulfuron Harbinger | NULL | 12098 | NULL |
| 359 | Sulfuronherold | NULL | 12098 | NULL |
| 541 | Firesworn | NULL | 12099 | NULL |
| 90 | Feueranbeter | NULL | 12099 | NULL |
| 557 | Lava Surger | NULL | 12101 | NULL |
| 215 | Lavawoger | NULL | 12101 | NULL |
| 556 | Lava Spawn | NULL | 12265 | NULL |
| 211 | Lavabrut | NULL | 12265 | NULL |
| 297 | Razzashi Raptor | NULL | 14821 | NULL |
| 301 | Razzashiraptor | NULL | 14821 | NULL |
+-----+--------------------------+--------------+--------------+-------+
44 rows in set (0.23 sec)
如何解决：
此查询会执行我想要的操作，但有一个问题，MySQL 无法更新用于 select 子查询的 Table。
UPDATE `character`
SET `character`.id_old = (
SELECT `character`.id
FROM `character`
GROUP BY `character`.id_new
HAVING COUNT(`character`.id_new) > 1
)
WHERE `character`.id_new IN (
SELECT `character`.id_new
FROM `character`
GROUP BY `character`.id_new
HAVING COUNT(`character`.id_new) > 1
);
所以我必须创建一个 temp_table 包含我需要的所有值：
CREATE TABLE `tmp_character` (
`id` INT(11) NULL DEFAULT NULL,
`id_new` INT(11) NULL DEFAULT NULL
)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
;
并用值填充它：
INSERT INTO tmp_character (id, id_new)
SELECT id, id_new
FROM `character`
WHERE id_new IN(
SELECT id_new
FROM `character`
GROUP BY `character`.id_new
HAVING COUNT(`character`.id_new) > 1
)
ORDER BY id_new ASC;
现在我得到了这个查询：
UPDATE `character`
SET `character`.id_old = (
SELECT tmp_character.id
FROM tmp_character
GROUP BY tmp_character.id_new
HAVING COUNT(tmp_character.id_new) > 1
)
WHERE `character`.id_new IN (
SELECT tmp_character.id_new
FROM tmp_character
GROUP BY tmp_character.id_new
HAVING COUNT(tmp_character.id_new) > 1
);
现在的问题：错误 1242 (21000)：子查询 returns 多于 1 行
没错，我有 22 个不同的 ID 要更新，我有 22 个组，不知道为什么它不起作用。
在此查询之后，我的 Table 应该如下所示：
+-----+--------------------------+--------------+--------------+-------+
| id | char_name_de | char_name_en | id_new | id_old|
+-----+--------------------------+--------------+--------------+-------+
| 258 | Natter | NULL | 2914 | 258 |
| 342 | Snake | NULL | 2914 | 342 |
| 290 | Rat | NULL | 4075 | 290 |
| 292 | Ratte | NULL | 4075 | 292 |
| 276 | Orakel der Hakkari | NULL | 11346 | 276 |
| 152 | Hakkari Oracle | NULL | 11346 | 152 |
| 148 | Gurubashi Warrior | NULL | 11355 | 148 |
| 201 | Krieger der Gurubashi | NULL | 11355 | 201 |
| 344 | Sohn von Hakkar | NULL | 11357 | 344 |
| 347 | Son of Hakkar | NULL | 11357 | 347 |
+-----+--------------------------+--------------+--------------+-------+
.
.
.
现在 "id_new" 应该像这样独一无二：
+-----+--------------------------+--------------+--------------+-------+
| id | char_name_de | char_name_en | id_new | id_old|
+-----+--------------------------+--------------+--------------+-------+
| 258 | Natter | NULL | 2914 | 258 |
| 290 | Rat | NULL | 4075 | 290 |
| 276 | Orakel der Hakkari | NULL | 11346 | 276 |
| 148 | Gurubashi Warrior | NULL | 11355 | 148 |
| 344 | Sohn von Hakkar | NULL | 11357 | 344 |
+-----+--------------------------+--------------+--------------+-------+
.
.
.
现在我想删除列 "id_new" 以获得最终的 table。
+-------+--------------------------+--------------+-------+
| id | char_name_de | char_name_en | id_old|
+-------+--------------------------+--------------+-------+
| 2914 | Natter | NULL | 258 |
| 4075 | Rat | NULL | 290 |
| 11346 | Orakel der Hakkari | NULL | 276 |
| 11355 | Gurubashi Warrior | NULL | 148 |
| 11357 | Sohn von Hakkar | NULL | 344 |
+-------+--------------------------+--------------+-------+
.
.
.
谁能帮我修改我的查询使其成为 运行？我需要在突出显示 "Now I've got this Query:" 后修复查询，其余的很容易，我自己得到它，我只是发布它，因为背景是我最后想要的。
这是我将值从 id 移动到 id_old 的脚本，其中我有不止一行：
<?php
function executeQuery($dbConnection, $Query) {
$result = $dbConnection -> query($Query);
return $result;
}
function openDB() {
$dbConnection= new mysqli($mServer, $mUser, $mPwd, $mDatabase);
return $dbConnection;
}
// open Database
$DBconnection=openDB();
// 1st query
$query="SELECT *
FROM `character` c
WHERE c.id_new IN(
SELECT c.id_new
FROM `character` c
GROUP BY id_new
HAVING COUNT(id_new) > 1
)
ORDER BY id_new ASC;";
// sent query to database
$result=executeQuery($DBconnection, $query);
$numRows=$result->num_rows;
// do as long as you've got rows
for(;$numRows>0;$numRows--) {
// go to next row
$currentRow=$result->fetch_object();
$id_new=$currentRow->id;
$query="UPDATE `character` c
SET c.class=" .$id_new ."
WHERE c.id IN(" .$id_new .");";
echo $query ."\n";
$result2=executeQuery($DBconnection, $query);
}
}
?>
这是第二个修改版本，如果一行加倍，它会删除第二行。如果一行会增加三倍或更多，那将不起作用！
<?php
function executeQuery($dbConnection, $Query) {
$result = $dbConnection -> query($Query);
return $result;
}
function openDB() {
$dbConnection= new mysqli($mServer, $mUser, $mPwd, $mDatabase);
return $dbConnection;
}
// open Database
$DBconnection=openDB();
// 1st query
$query="SELECT *
FROM `character`
WHERE id_new IN(
SELECT id_new
FROM `character`
GROUP BY `character`.id_new
HAVING COUNT(`character`.id_new) > 1
)
ORDER BY id_new ASC;";
// send query to database
$result=executeQuery($DBconnection, $query);
$numRows=$result->num_rows;
// as long as you've got rows
for(;$numRows>0;$numRows--) {
// go to next row
$currentRow=$result->fetch_object();
for($i=0;$i<2;$i++) {
if($i==0) {
// skip 1st line from each row which is doubled
$currentRow=$result->fetch_object();
}
// delete 2nd line from each row which is doubled
$id_new=$currentRow->id;
$query="delete from `character`where id=" .$id_new .";";
$result2=executeQuery($DBconnection, $query);
}
}
?>
但正如我所说，这是一个肮脏的脚本！
它是如何工作的？
我在第二个查询中使用了一个查询的一些值。我保证它在没有 php 的情况下也能工作，但有时一个快速而肮脏的解决方案比一个需要几天的好解决方案更好！
//关闭
我正在开发 MaNGOS 数据库。目前我有自己的 id，但我想使用官方一次。问题是我的数据库中已经有一些我想更新的值。
我要更新的table是这样的
mysql> SELECT * FROM `character` LIMIT 10;
+----+---------------------------------+--------------+--------------+-------+
| id | char_name_de | char_name_en | id_new | id_old|
+----+---------------------------------+--------------+--------------+-------+
| 1 | | NULL | 2 | NULL |
| 2 | Abgesandter des Schattenhammers | NULL | 18201 | NULL |
| 3 | Abgesplittertes Skelett | NULL | 10478 | NULL |
| 4 | Adept aus Scholomance | NULL | 10469 | NULL |
| 5 | Aduscha | NULL | 18204 | NULL |
| 6 | Aggressiver Bluthund | NULL | 8922 | NULL |
| 7 | Akolyt aus Scholomance | NULL | 10471 | NULL |
| 8 | Akolyt der Schmetterschilde | NULL | 9045 | NULL |
| 9 | Althena | NULL | 18208 | NULL |
| 10 | Amadelis | NULL | 18209 | NULL |
+----+---------------------------------+--------------+--------------+-------+
10 rows in set (0.00 sec)
我正在尝试做的事情： 将 "id" 替换为 "new_id"
问题： "id_new" 不是某些多语言字符串的唯一原因。 我想匹配成一行，把"id"存到"id_old"，把"id"换成"id_new"删除"id_new".
看起来像这样：
mysql> SELECT *
-> FROM `character`
-> WHERE id_new IN(
-> SELECT id_new
-> FROM `character`
-> GROUP BY `character`.id_new
-> HAVING COUNT(`character`.id_new) > 1
-> )
-> ORDER BY id_new ASC;
+-----+--------------------------+--------------+--------------+-------+
| id | char_name_de | char_name_en | id_new | id_old|
+-----+--------------------------+--------------+--------------+-------+
| 258 | Natter | NULL | 2914 | NULL |
| 342 | Snake | NULL | 2914 | NULL |
| 290 | Rat | NULL | 4075 | NULL |
| 292 | Ratte | NULL | 4075 | NULL |
| 276 | Orakel der Hakkari | NULL | 11346 | NULL |
| 152 | Hakkari Oracle | NULL | 11346 | NULL |
| 148 | Gurubashi Warrior | NULL | 11355 | NULL |
| 201 | Krieger der Gurubashi | NULL | 11355 | NULL |
| 344 | Sohn von Hakkar | NULL | 11357 | NULL |
| 347 | Son of Hakkar | NULL | 11357 | NULL |
| 47 | Bloodseeker Bat | NULL | 11368 | NULL |
| 51 | Blutsucherfledermaus | NULL | 11368 | NULL |
| 560 | Molten Giant | NULL | 11658 | NULL |
| 123 | Geschmolzener Riese | NULL | 11658 | NULL |
| 545 | Flamewaker | NULL | 11661 | NULL |
| 93 | Feuerschuppe | NULL | 11661 | NULL |
| 546 | Flamewaker Priest | NULL | 11662 | NULL |
| 94 | Feuerschuppenpriester | NULL | 11662 | NULL |
| 553 | Lava Annihilator | NULL | 11665 | NULL |
| 214 | Lavavernichter | NULL | 11665 | NULL |
| 540 | Firelord | NULL | 11668 | NULL |
| 92 | Feuerlord | NULL | 11668 | NULL |
| 543 | Flame Imp | NULL | 11669 | NULL |
| 104 | Flammenwichtel | NULL | 11669 | NULL |
| 536 | Core Hound | NULL | 11671 | NULL |
| 194 | Kernhund | NULL | 11671 | NULL |
| 534 | Ancient Core Hound | NULL | 11673 | NULL |
| 384 | Uralter Kernhund | NULL | 11673 | NULL |
| 549 | Golemagg the Incinerator | NULL | 11988 | NULL |
| 129 | Golemagg der Verbrenner | NULL | 11988 | NULL |
| 558 | Majordomo Executus | NULL | 12018 | NULL |
| 240 | Majordomus Exekutus | NULL | 12018 | NULL |
| 554 | Lava Elemental | NULL | 12076 | NULL |
| 212 | Lavaelementar | NULL | 12076 | NULL |
| 564 | Sulfuron Harbinger | NULL | 12098 | NULL |
| 359 | Sulfuronherold | NULL | 12098 | NULL |
| 541 | Firesworn | NULL | 12099 | NULL |
| 90 | Feueranbeter | NULL | 12099 | NULL |
| 557 | Lava Surger | NULL | 12101 | NULL |
| 215 | Lavawoger | NULL | 12101 | NULL |
| 556 | Lava Spawn | NULL | 12265 | NULL |
| 211 | Lavabrut | NULL | 12265 | NULL |
| 297 | Razzashi Raptor | NULL | 14821 | NULL |
| 301 | Razzashiraptor | NULL | 14821 | NULL |
+-----+--------------------------+--------------+--------------+-------+
44 rows in set (0.23 sec)
如何解决： 此查询会执行我想要的操作，但有一个问题，MySQL 无法更新用于 select 子查询的 Table。
UPDATE `character`
SET `character`.id_old = (
SELECT `character`.id
FROM `character`
GROUP BY `character`.id_new
HAVING COUNT(`character`.id_new) > 1
)
WHERE `character`.id_new IN (
SELECT `character`.id_new
FROM `character`
GROUP BY `character`.id_new
HAVING COUNT(`character`.id_new) > 1
);
所以我必须创建一个 temp_table 包含我需要的所有值：
CREATE TABLE `tmp_character` (
`id` INT(11) NULL DEFAULT NULL,
`id_new` INT(11) NULL DEFAULT NULL
)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
;
并用值填充它：
INSERT INTO tmp_character (id, id_new)
SELECT id, id_new
FROM `character`
WHERE id_new IN(
SELECT id_new
FROM `character`
GROUP BY `character`.id_new
HAVING COUNT(`character`.id_new) > 1
)
ORDER BY id_new ASC;
现在我得到了这个查询：
UPDATE `character`
SET `character`.id_old = (
SELECT tmp_character.id
FROM tmp_character
GROUP BY tmp_character.id_new
HAVING COUNT(tmp_character.id_new) > 1
)
WHERE `character`.id_new IN (
SELECT tmp_character.id_new
FROM tmp_character
GROUP BY tmp_character.id_new
HAVING COUNT(tmp_character.id_new) > 1
);
现在的问题：错误 1242 (21000)：子查询 returns 多于 1 行 没错，我有 22 个不同的 ID 要更新，我有 22 个组，不知道为什么它不起作用。
在此查询之后，我的 Table 应该如下所示：
+-----+--------------------------+--------------+--------------+-------+
| id | char_name_de | char_name_en | id_new | id_old|
+-----+--------------------------+--------------+--------------+-------+
| 258 | Natter | NULL | 2914 | 258 |
| 342 | Snake | NULL | 2914 | 342 |
| 290 | Rat | NULL | 4075 | 290 |
| 292 | Ratte | NULL | 4075 | 292 |
| 276 | Orakel der Hakkari | NULL | 11346 | 276 |
| 152 | Hakkari Oracle | NULL | 11346 | 152 |
| 148 | Gurubashi Warrior | NULL | 11355 | 148 |
| 201 | Krieger der Gurubashi | NULL | 11355 | 201 |
| 344 | Sohn von Hakkar | NULL | 11357 | 344 |
| 347 | Son of Hakkar | NULL | 11357 | 347 |
+-----+--------------------------+--------------+--------------+-------+
.
.
.
现在 "id_new" 应该像这样独一无二：
+-----+--------------------------+--------------+--------------+-------+
| id | char_name_de | char_name_en | id_new | id_old|
+-----+--------------------------+--------------+--------------+-------+
| 258 | Natter | NULL | 2914 | 258 |
| 290 | Rat | NULL | 4075 | 290 |
| 276 | Orakel der Hakkari | NULL | 11346 | 276 |
| 148 | Gurubashi Warrior | NULL | 11355 | 148 |
| 344 | Sohn von Hakkar | NULL | 11357 | 344 |
+-----+--------------------------+--------------+--------------+-------+
.
.
.
现在我想删除列 "id_new" 以获得最终的 table。
+-------+--------------------------+--------------+-------+
| id | char_name_de | char_name_en | id_old|
+-------+--------------------------+--------------+-------+
| 2914 | Natter | NULL | 258 |
| 4075 | Rat | NULL | 290 |
| 11346 | Orakel der Hakkari | NULL | 276 |
| 11355 | Gurubashi Warrior | NULL | 148 |
| 11357 | Sohn von Hakkar | NULL | 344 |
+-------+--------------------------+--------------+-------+
.
.
.
谁能帮我修改我的查询使其成为 运行？我需要在突出显示 "Now I've got this Query:" 后修复查询，其余的很容易，我自己得到它，我只是发布它，因为背景是我最后想要的。
这是我将值从 id 移动到 id_old 的脚本，其中我有不止一行：
<?php
function executeQuery($dbConnection, $Query) {
$result = $dbConnection -> query($Query);
return $result;
}
function openDB() {
$dbConnection= new mysqli($mServer, $mUser, $mPwd, $mDatabase);
return $dbConnection;
}
// open Database
$DBconnection=openDB();
// 1st query
$query="SELECT *
FROM `character` c
WHERE c.id_new IN(
SELECT c.id_new
FROM `character` c
GROUP BY id_new
HAVING COUNT(id_new) > 1
)
ORDER BY id_new ASC;";
// sent query to database
$result=executeQuery($DBconnection, $query);
$numRows=$result->num_rows;
// do as long as you've got rows
for(;$numRows>0;$numRows--) {
// go to next row
$currentRow=$result->fetch_object();
$id_new=$currentRow->id;
$query="UPDATE `character` c
SET c.class=" .$id_new ."
WHERE c.id IN(" .$id_new .");";
echo $query ."\n";
$result2=executeQuery($DBconnection, $query);
}
}
?>
这是第二个修改版本，如果一行加倍，它会删除第二行。如果一行会增加三倍或更多，那将不起作用！
<?php
function executeQuery($dbConnection, $Query) {
$result = $dbConnection -> query($Query);
return $result;
}
function openDB() {
$dbConnection= new mysqli($mServer, $mUser, $mPwd, $mDatabase);
return $dbConnection;
}
// open Database
$DBconnection=openDB();
// 1st query
$query="SELECT *
FROM `character`
WHERE id_new IN(
SELECT id_new
FROM `character`
GROUP BY `character`.id_new
HAVING COUNT(`character`.id_new) > 1
)
ORDER BY id_new ASC;";
// send query to database
$result=executeQuery($DBconnection, $query);
$numRows=$result->num_rows;
// as long as you've got rows
for(;$numRows>0;$numRows--) {
// go to next row
$currentRow=$result->fetch_object();
for($i=0;$i<2;$i++) {
if($i==0) {
// skip 1st line from each row which is doubled
$currentRow=$result->fetch_object();
}
// delete 2nd line from each row which is doubled
$id_new=$currentRow->id;
$query="delete from `character`where id=" .$id_new .";";
$result2=executeQuery($DBconnection, $query);
}
}
?>
但正如我所说，这是一个肮脏的脚本！
它是如何工作的？ 我在第二个查询中使用了一个查询的一些值。我保证它在没有 php 的情况下也能工作，但有时一个快速而肮脏的解决方案比一个需要几天的好解决方案更好！
//关闭