按相反顺序按内部对象（字符串、日期等）对 ArrayList<Object[]> 进行排序

Question

假设有一个ArrayList<Object[]>，里面包含各种对象：

ArrayList<Object[]> list = new ArrayList<>();
list.add(new Object[]{"cat", (long)1422355945});
list.add(new Object[]{"dog", (long)1422355970});
list.add(new Object[]{"rat", (long)1422355900});

我们如何才能有效地按照第一个Object（即String）的倒序对这个列表进行排序？并在第二个 Object（即 long）之前做同样的事情？

Answer 1

只需创建一个比较器，类似于下面的示例：

    List<Object[]> list = new ArrayList<>();
    list.add(new Object[] { "cat", (long) 1422355945 });
    list.add(new Object[] { "dog", (long) 1422355970 });
    list.add(new Object[] { "rat", (long) 1422355900 });

    Collections.sort(list, new Comparator<Object[]>() {
        @Override
        public int compare(Object[] o1, Object[] o2) {
            int cmp1 = ((String) o1[0]).compareTo((String) o2[0]);
            if (cmp1 == 0) {
                return Long.compare((Long) o1[1], (Long) o2[1]);
            }
            return cmp1;
        }
    });

按相反顺序按内部对象（字符串、日期等）对 ArrayList<Object[]> 进行排序

Sorting ArrayList<Object[]> by objects inside (String, Date, etc.) in reverse order

java

sorting

arraylist