如何在另一个自定义 JsonSerializer Jackson 中调用 JsonSerializer

Question

我有两个 class。首先是第二个 class.

的字段

class A {
  @JsonSerializer(using = CustomBSerializer.class)
  private B b;
}

class B {
  ...
}

我有两个自定义序列化程序：

class CustomBSerializer extends JsonSerializer<B> {
  ...
}

class CustomASerializer extends JsonSerializer<A> {
    @Override
    public void serialize(A a, JsonGenerator jgen, SerializerProvider provider)
            throws IOException, JsonProcessingException {
        jgen.writeStartObject();
        //write here
        jgen.writeEndObject();
    }

}

我应该添加什么方法而不是在 CustomASerializer 中添加注释来用 CustomBSerializer 写入字段 b 的序列化值？

Answer 1

您可以使用writeObjectField方法。 Jackson 应使用默认或自定义序列化程序（如果存在）。

下面的例子：

import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializerProvider;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;

import java.io.IOException;
import java.util.Date;

public class Main {

    public static void main(String[] args) throws Exception {
        B b = new B();
        b.setProperty("Value");

        A a = new A();
        a.setB(b);

        ObjectMapper mapper = new ObjectMapper();
        System.out.println(mapper.writerWithDefaultPrettyPrinter().writeValueAsString(a));
    }
}

@JsonSerialize(using = ASerializer.class)
class A {

    private B b;

    public B getB() {
        return b;
    }

    public void setB(B b) {
        this.b = b;
    }
}

class ASerializer extends JsonSerializer<A> {

    @Override
    public void serialize(A value, JsonGenerator gen, SerializerProvider serializers) throws IOException, JsonProcessingException {
        gen.writeStartObject();
        gen.writeStringField("now", new Date().toString());
        gen.writeObjectField("b", value.getB());
        gen.writeEndObject();
    }
}

@JsonSerialize(using = BSerializer.class)
class B {

    private String property;

    public String getProperty() {
        return property;
    }

    public void setProperty(String property) {
        this.property = property;
    }
}

class BSerializer extends JsonSerializer<B> {

    @Override
    public void serialize(B value, JsonGenerator gen, SerializerProvider serializers) throws IOException, JsonProcessingException {
        gen.writeStartObject();
        gen.writeStringField("p", value.getProperty());
        gen.writeEndObject();
    }
}

打印：

{
  "now" : "Wed Aug 26 22:27:08 CEST 2015",
  "b" : {
    "p" : "Value"
  }
}

Answer 2

您并不总是可以访问 class 代码，您不会总是有可能修改 A 或 B class 以放置注释 @JsonSerialize(using = BSerializer.class).在这些情况下，您需要在 CustomASerializer 中调用 CustomBSerializer，这也是问题首先提出的问题。这是这样做的方法：

class CustomASerializer extends JsonSerializer<A> {

    @Override
    public void serialize(A a, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonProcessingException {

        final ObjectMapper mapper = (ObjectMapper)jgen.getCodec();
        SimpleModule module =  new SimpleModule("CustomBSerializer");
        module.addSerializer(B.class, new CustomBSerializer());
        mapper.registerModule(module);

        jgen.writeStartObject();
        mapper.writeValue(jgen, a.getB());
        jgen.writeEndObject();
    }

}

如何在另一个自定义 JsonSerializer Jackson 中调用 JsonSerializer

How to invoke JsonSerializer inside another custom JsonSerializer Jackson

java

json

jackson