拆分字符串并将特定字符串提取到数组

Question

我有一个字符串 "S"。只有单引号中的子字符串必须分配给一个字符串 Array.Its 可能没有必要在单引号中替换单词。

String S = "Username 'user1'
             Username2 'user2'
             Usermane3 'user3' 'user4'";

必须如下赋值（仅限带单引号的子串）

 String Username[] ={'user','user1','user2','user4'};

我试过的

 String s1 = S.replace(System.getProperty("line.separator"), " ");
   //replacing newline with single space
 String Username[] = s1.split(" ");
  //separating string into sub-string
 Username[]={Username,'user1',Username2,'user2',Username3, 'user3','user4'};

Answer 1

您可以使用定界符拆分输入并获取备用字符串。

String S = "Username 'user1' Username2 'user2 user21' Usermane3 'user3'";
String[] tokens = S.split("'");//use delimiter as ' to get the value inside the quote
String[] usernames = new String[tokens.length / 2];
for (int i = 1, k = 0; i < tokens.length; i += 2) {
    System.out.println(tokens[i]);
    usernames[k++] = tokens[i];
}

如果没有规定单人Username会有单人user1喜欢

String S = "Username 'user1' Username2 'user2' Usermane3 'user3' 'user4'";

您可以使用逻辑仅获取引号中的字符串，如下所示。

String S = "Username 'user1' Username2 'user2' Usermane3 'user3' 'user4'";
ArrayList<String> words = new ArrayList();
String word = "";
boolean startQuote = false;
for (int i = 0; i < S.length(); ++i) {
    char ch = S.charAt(i);
    if (ch == '\'') {
        if (word.equals(""))
            startQuote = true;
        else {
            words.add(word);
            word = "";
            startQuote = false;
            }
        }
    else if (startQuote) {
        word += ch;
    }
}
System.out.println(words);

Answer 2

这将按照@Uma Kanth 的版本中的描述漂亮地打印数组。如果你需要的话。

System.out.print("usernames = [");
for (int i = 0; i < usernames.length; i++) {
    String username = usernames[i];
    System.out.print(username);
    if (i < usernames.length - 1) {
        System.out.print(", ");
    }
}
System.out.println("]");

拆分字符串并将特定字符串提取到数组

Splitting a string and extracting specific strings to array

java

arrays

substring