将具有特定值的列更新为具有相同 ID 的列值

Question

我的Table：

 ID | Number
-------------------
| 1 | 0x
| 1 | 12345678
| 1 | 12345678
| 2 | 0x
| 2 | 0x
| 2 | 242424
| 3 | 88888
| 3 | 88888
| 4 | 0x
| 4 | 0x

Table 必须更新，以便每个“0x”都将更新为正确的 'Number'（如果存在的话）。

需要的结果：

ID | Number
-------------------
| 1 | 12345678      <-- Updated
| 1 | 12345678
| 1 | 12345678
| 2 | 242424        <-- Updated
| 2 | 242424        <-- Updated
| 2 | 242424
| 3 | 88888         <- No change on id = 3
| 3 | 88888         <- No change on id = 3
| 4 | 0x            <- No change because there's no relevant 'Number' to update 
| 4 | 0x            <- No change because there's no relevant 'Number' to update

Answer 1

Demo of the following query

;WITH CTE AS (
    SELECT Id, Max(number) Number
    FROM YourTable
    WHERE Number <> '0x'
    GROUP BY Id
)
UPDATE ut SET Number = c.Number
FROM YourTable ut
    JOIN CTE c ON ut.Id = c.Id
WHERE ut.Number = '0x'

将具有特定值的列更新为具有相同 ID 的列值

Update column with certain value to a column value with same id

sql

sql-server

sql-update