E/SQLiteLog﹕ (1) near "Table": 语法错误

Question

我正尝试在 android 中使用 SQLite，但我遇到了一些问题..
我从 2012 年编写的教程中获取了代码，但它现在对我不起作用并显示此错误：

E/SQLiteLog﹕ (1) near "Table": syntax error

问题出在 creating/opening 数据库上。

package db.com.example.kids1.databasetest;

import android.app.ListActivity;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteException;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.TextView;

import org.w3c.dom.Text;

import java.io.IOException;
import java.util.ArrayList;

public class MainActivity extends ListActivity{

    private final String DB_NAME = "Database";
    private final String TABLE_NAME = "Table";
    SQLiteDatabase DB = null;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        ArrayList<String> results = new ArrayList<>();

        String[] res = {"Red", "Green", "Text"};



        try {
            DB = this.openOrCreateDatabase(DB_NAME, MODE_PRIVATE, null);
            DB.execSQL("CREATE TABLE IF NOT EXISTS " +
                TABLE_NAME +
                "(Name VARCHAR, Street VARCHAR, Block INT, City VARCHAR, Tel VARCHAR);");
            mFillDbsTable();

            Cursor c = DB.rawQuery("SELECT Name, Street, Block, City, Tel FROM " +
                    TABLE_NAME +
                    " where Blcok == 9 LIMIT 5", null);
            if (c!=null){

                if (c.moveToFirst()) {
                    do {

                        String name = c.getString(c.getColumnIndex("Name"));
                        String street = c.getString(c.getColumnIndex("Street"));
                        int block = c.getInt(c.getColumnIndex("Block"));
                        String city = c.getString(c.getColumnIndex("City"));
                        String tel = c.getString(c.getColumnIndex("Tel"));

                        results.add(name + "," + street + "," + block + "," + city + "," + tel);
                    } while (c.moveToNext());
                }
            }

            ListView list = (ListView)findViewById(android.R.id.list);


            ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, res);

            list.setAdapter(adapter);

        } catch (SQLiteException se){
            Log.e(getClass().getSimpleName(), "Create/Open Database Problem.");
        }

    }

    private void mFillDbsTable(){

        try {
            DB.execSQL("INSERT INTO " +
                    TABLE_NAME +
                    " Values('Noam', 'Shkolnik', 9, 'Rehovot', '054-4900807');");

            DB.execSQL("INSERT INTO " +
                    TABLE_NAME +
                    " Values('Eyal', 'Shkolnik', 9, 'Rehovot', '055-4488779');");

            DB.execSQL("INSERT INTO " +
                    TABLE_NAME +
                    " Values('Yehontan', 'Shkolnik', 9, 'Rehovot', '058-7789547');");
        } catch (SQLiteException se) {
            Log.e(getClass().getSimpleName(), "Could not create records.");
        }

    }
}

Answer 1

尝试 VARCHAR(100) 并删除结尾的 ;

Answer 2

private final String TABLE_NAME = "Table"

您无法创建名为 Table 的 table，因为它是保留关键字。
您最好创建一个名为 MyTable 的 table（或 _Table 或更好地给出一个更健谈的名称，例如 Persons - 注意 s 表示复数）。

所以：

private final String TABLE_NAME = "MyTable"

供您参考：https://sqlite.org/lang_keywords.html

您可以（但不推荐）使用保留关键字，但每次引用该关键字时都必须使用特殊分隔符table。

类似

private final String TABLE_NAME = "[Table]"

而且您的查询中还有另一个（双重）错误：

" where Blcok == 9 LIMIT 5"

应该是

" where Block = 9 LIMIT 5"

Answer 3

你有几个错误。首先，不要将您的 table 命名为 Table。 Table是保留字（see docs），不能直接使用。基本不建议使用保留字，所以我建议你改一下你的table名称，但如果你坚持使用它，你需要先引用它：

If you want to use a keyword as a name, you need to quote it. There are four ways of quoting keywords in SQLite:

'keyword' A keyword in single quotes is a string literal.

"keyword" A keyword in double-quotes is an identifier.

[keyword] A keyword enclosed in square brackets is an identifier. This is not standard SQL. This quoting mechanism is used by MS Access and SQL Server and is included in SQLite for compatibility.

keyword A keyword enclosed in grave accents (ASCII code 96) is an identifier. This is not standard SQL. This quoting mechanism is used by MySQL and is included in SQLite for compatibility.

顺便说一句：由于 where 子句中的拼写错误，您的进一步 select 查询也会失败：

where Blcok == 9

E/SQLiteLog﹕ (1) near "Table": 语法错误

E/SQLiteLog﹕ (1) near "Table": syntax error

sql

sqlite

android

syntax-error