在 UNION mysql 中仅在一个查询中排序

Question

我有一个table

Table 用户

 Id      Name     status        
 1       Jhon     Approved        
 2       Endy     Decline
 3       Ally     In Review

我必须显示所有用户的列表并仅对那些未获批准的行进行排序。

我的代码如下

(select name from user where status<>'Approved' order by status asc)
UNION  
(select name from user where status='Approved')

我总是在 ASC 和 DESC

这两种情况下得到这个

Id      Name     status             
 3      Ally     In Review
 2      Endy     Decline
 1      Jhon     Approved

name 的订单结果也应该相同。

(select name from user where status<>'Approved' order by name asc)
UNION  
(select name from user where status='Approved')

 Id      Name     status             
 3       Ally     In Review
 2       Endy     Decline
 1       Jhon     Approved

请帮助我。您的帮助将不胜感激。

Answer 1

您可以使用 case when 作为 order by

select * from User 
order by  
case when status <> 'Approved' then 0 else 1 end ,status;

Answer 2

尝试将 union 更改为 union all，它至少在 oracle 中有效

select * from 
(select * from t1 where status <> 'Approved' order by status asc)
union all
select * from 
(select * from t1 where status = 'Approved' )

输出：

ID|NAME|STATUS
2|Endy|Declined
3|Ally|In Review
1|John|Approved

希望对您有所帮助。 :)

Answer 3

感谢您的回复。我得到了解决方案

(select * from 
(select * from user where status <> 'Approved' order by status asc) a)
union 
(select * from t1 where status = 'Approved' )

在 UNION mysql 中仅在一个查询中排序

order by in only one query in UNION mysql

mysql

union