代码重构以删除重复的正则表达式

Question

我写了下面一段 Ruby 代码，用于从 html 页面中提取信息。

  combined = state = county = special = 0

  unless options.nil?

    unless /([0-9\.]+)% \(Combined\)/.match(options).nil?
      combined = /([0-9\.]+)% \(Combined\)/.match(options)[1].to_f
    end

    unless /([0-9\.]+)% \(State\)/.match(options).nil?
      state = /([0-9\.]+)% \(State\)/.match(options)[1].to_f
    end

    unless /([0-9\.]+)% \(County\)/.match(options).nil?
      county = /([0-9\.]+)% \(County\)/.match(options)[1].to_f
    end

    unless /([0-9\.]+)% \(Special\)/.match(options).nil?
      special = /([0-9\.]+)% \(Special\)/.match(options)[1].to_f
    end

    if combined==0 and state==0 and county==0 and special ==0 then
      unless />([0-9\.]+)%</.match(options).nil?
        combined = />([0-9\.]+)%</.match(options)[1].to_f
      end          
    end

  end

我应该如何重构此代码以消除每个正则表达式的重复？

Answer 1

更新：相同的方法，但稍微清理了代码

results = Hash.new(0)
if options
  %w(Combined State County Special).each do |query|
    options =~ /([0-9\.]+)% \(#{query}\)/
    results[query.downcase.intern] = .to_f if $~
  end

  if results.values.all?(&:zero?)
    options =~ />([0-9\.]+)%</
    results[:combined] = .to_f if $~
  end
end

Answer 2

return if options.nil?
options.scan(/([0-9.]+)% \(([\w]+)\)/) do
  case 
  when "Combined".freeze then combined = .to_f
  when "State".freeze    then state    = .to_f
  when "County".freeze   then county   = .to_f
  when "Special".freeze  then special  = .to_f
  else
    combined = .to_f if options =~ />([0-9.]+)%</
  end
end

代码重构以删除重复的正则表达式

Code refactoring to remove repetitions of regular expressions

ruby

refactoring