Python线程给定了一个以上的参数

Question

我正在尝试启动线程，但我不断收到错误消息，提示我正在尝试发送多个参数。 Thread 对象似乎没有将变量端口作为一个参数，而是将字符串中的每个字符作为一个单独的参数。这是如何工作的？这是我第一次在 python.

中使用多线程

错误信息：

Exception in thread /dev/ttyUSB0:
Traceback (most recent call last):
  File "/usr/lib/python2.7/threading.py", line 810, in __bootstrap_inner
    self.run()
  File "/usr/lib/python2.7/threading.py", line 763, in run
    self.__target(*self.__args, **self.__kwargs)
TypeError: report() takes exactly 1 argument (12 given)

代码：

def report(port):
    print("\n")
    print(st() +"Connecting to" + port[0]) 

    device = serial.Serial(port=port[0], baudrate=9600, timeout=0.2)

    print (st() + "Connection sucessfull...")       
    print (st() + "Initializing router on "+ port[0])
    if initialize_router(device) == 0:
        return 0

    print (st() + "Initialization sucessfull")
    print (st() + "Starting to inject IP basic config")
    if inject_config(device) == 0:
        print(errror("injecing the confing",port[0]))
        return 0

    print(st()+ "Finished injecting default IP setting on router connected to " + port[0])

    return 1

if __name__ == '__main__':  
    ports = list_ports.comports()
    list_port = list(ports)
    port_counter = -1
    for port in list_port:
        if "USB" in port[0]:
            port_counter = port_counter + 1
            port = "/dev/ttyUSB" + str(port_counter)
            thread = Thread(target=report, args=(port), name=port)
            thread.start()
            print port
            print ("\n")
            continue

Answer 1

        thread = Thread(target=report, args=(port), name=port)

我猜您想在这里将单个元素元组传递给 args。但是 port 周围的括号本身没有任何作用。尝试：

        thread = Thread(target=report, args=(port,), name=port)

Python线程给定了一个以上的参数

Python Threading More then one agrument given

python

multithreading

arguments