Java :在 while 循环中嵌套 if/else 语句

Java : Nesting an if/else statement inside a while loop

这是我在 Whosebug 中的第一个问题,因此我希望您能原谅我在设置此问题时可能会犯的许多错误 post... 我的问题如下:这段代码应该生成一个随机数,将其显示给用户(为了帮助我猜测它而无需进行太多尝试......这应该只是一个练习),要求用户猜测一个数字在 0 到 50 之间,检查输入是否为整数,如果用户猜对了数字,则打印 "Yes, the number is.." 。 但是,如果用户输入一个字母或任何不是数字的数字,if/else 循环就会变得疯狂,程序开始打印 "Choose a number between 0 and 50: Please insert a number between 0 and 50, not a letter" 而不会停止...... 任何人都可以帮助我吗?

package methods;

import java.util.Scanner;

public class Methods {

    static int randomNumber;
    static Scanner userInput = new Scanner(System.in);

    public static void main(String[] args) {

        System.out.println(getRandomNum());

        int guessResult = 1;
        int randomGuess = 0;

        while (guessResult != -1) {
            System.out.print("Choose a number between 0 and 50: ");

            if (userInput.hasNextInt()) {
                randomGuess = userInput.nextInt();
                guessResult = checkGuess(randomGuess);
            } else {

                System.out.println("Please insert  a number, not  a letter");
            }

        }

        System.out.println("Yes, the number is " + randomGuess);
    }

    public static int getRandomNum() {

        randomNumber = (int) (Math.random() * 51);
        return randomNumber;

    }

    public static int checkGuess(int guess) {

        if (guess == randomNumber) {

            return -1;
        } else {

            return guess;

        }
    }
}

您允许用户输入一个字母(意图给出错误消息,但您只调用 scanner.nextInt)

您应该将输入读取为字符串,然后对其进行解析。

    String input = null;
    while (guessResult != -1) {
        System.out.print("Choose a number between 0 and 50: ");

        input = sc.next();
        try
        {
            randomGuess = Integer.parseInt(input);
            checkGuess(randomGuess);
        } catch(NumberFormatException ex)
        {
            System.out.println("Please insert  a number, not  a letter");
        }

    }