FIFO Class 实施不工作

Question

我在下面创建了一个简单的 FIFO class：

class Queue:

    # Constructor, which creates a new empty queue:
    def __init__(self):
        self.items = []
        # TODO: You must implement this constructor!

    # Adds a new item to the back of the queue, and returns nothing:
    def queue(self, item):
        return self.items.append(item)
        # TODO: You must implement this method!

    # Removes and returns the front-most item in the queue.  
    # Returns nothing if the queue is empty.
    def dequeue(self):
        if len(self.items)==0:
            return None
        else:
            return self.items.pop(0)
        # TODO: You must implement this method!

    # Returns the front-most item in the queue, and DOES NOT change the queue.  
    def peek(self):
        if len(self.items)==0:
            return None

        else:

            return self.items[0]
        # TODO: You must implement this method!

    # Returns True if the queue is empty, and False otherwise:
    def is_empty(self):
        return self.items == []
        # TODO: You must implement this method!

    # Returns the number of items in the queue:
    def size(self):
        return len(self.items)
        # TODO: You must implement this method!

    # Removes all items from thq queue, and sets the size to 0:
    def clear(self):
        while len(self.items) > 0:
            self.items.pop()
        # TODO: You must implement this method!

    # Returns a string representation of the queue:
    def __str__(self):
        return repr(self.items)
        # TODO: You must implement this method!

然而，当在另一个文件中使用class时，dequeue()方法似乎不起作用，我正在尝试实现一个杂货店阵容，需求如下：

该计划不得允许超过 3 人参加一次。如果用户在以下时间尝试将另一个人添加到阵容中已经有 3 个人，程序应该打印错误消息并继续。

如果用户在没有人的情况下试图为下一个人服务阵容，程序应该通知用户阵容是空的。当一个人被送达时，程序应该打印那个人的名字人.

这是我尝试实施和使用 class:

时的另一个文件

from queue import Queue
q=Queue()
exit==False 



ase=input("Add, Serve, or Exit: ")
while ase=="Serve"  and q.is_empty()== True and exit==False:
    print("The lineup is already empty.")
    ase=input("Add, Serve, or Exit: ")
    if ase=="Exit":
        exit==True

while (q.size()<3 and ase== "Add") or (q.size()<3 and ase== "Serve"):
    add=input("Enter the name of the person to add: ")
    ase=input("Add, Serve, or Exit: ")

    q.queue(add)
    print(q.__str__())
    while q.size()==3 and ase=="Add":
        print("You cannot add more people, the lineup is full!")
        ase=input("Add, Serve, or Exit: ")

    while ase=="Serve" and q.is_empty()==False and exit==False:
        print(q.dequeue(), "has been served")

我知道它实际上将名称添加到列表中，但我不知道为什么当输入为 "Serve"

时它什么都不做

同样在开始时，当我想让它打印 ("line up empty") 时，它甚至没有到达那一行。想法？

Answer 1

在我看来，您的 exit 变量有问题：它在第一个循环结束时设置为 True。但是你的 Serve 循环期望它是 False 进入...

while ase=="Serve"  and q.is_empty()== True and exit==False:
    print("The lineup is already empty.")
    ase=input("Add, Serve, or Exit: ")
    if ase=="Exit":
        exit==True
#       ^^^^^^^^^^

...

    while ase=="Serve" and q.is_empty()==False and exit==False:
#                                                  ^^^^^^^^^^^
        print(q.dequeue(), "has been served")

Answer 2

我解决了！这是我使用 class:

的最终代码

from queue import Queue
q=Queue()
exit==False 



ase=input("Add, Serve, or Exit: ")
while ase=="Serve" and q.is_empty()==True:
    print("The lineup is already empty.")
    ase=input("Add, Serve, or Exit: ")
    if ase=="Exit":
        break

while (q.size()<3 and ase== "Add"):
    add=input("Enter the name of the person to add: ")
    ase=input("Add, Serve, or Exit: ")

    q.queue(add)
    print(q.__str__())
    while q.size()==3 and ase=="Add":
        print("You cannot add more people, the lineup is full!")
        ase=input("Add, Serve, or Exit: ")

    while ase=="Serve":
        print(q.dequeue(), "has been served")
        ase=input("Add, Serve, or Exit: ")

Answer 3

与其使用多个 while（带有一些叠层），您应该只使用一个带有条件分支的 while 来管理不同的命令（add/server/exit，等等）。这样会更清晰，也更容易修改。

我建议这样：

ase = raw_input("Add, Serve, or Exit: ")
while ase != "Exit":
  if ase == "Serve":
    if q.is_empty():
      print("The lineup is already empty.")
    else:
      # dequeue + message
  elif ase == "Add":
    if q.size() == 3:
      print("You cannot add more people, the lineup is full!")
    else:
      add = raw_input("Enter the name of the person to add: ")
      # enqueue add + message
  else:
    print("invalid command...")

  ase = raw_input("Add, Serve, or Exit: ")

FIFO Class 实施不工作

FIFO Class Implemenation Not Working

python

python-3.x