获取数据 employee table with 1 id and multiple transaction id

Question

此处交易 table 一名员工有多项交易。我想要 1 名特定员工的所有交易。但员工 ID 应在列中打印一次。这里是格式

1.here一名员工有多个交易id .id应该显示1次并显示所有交易

期望的结果：员工详细信息应显示在一行中，但交易 ID 应显示在多行中

错误 ID 重复 ID：

从评论中复制：

select 
  b.TransactionId,
  a.Name
from 
  TransactionRecharge b 
  left JOIN Customer a on a.Id=b.CustomerId 
where 
  b.CustomerId=101282

Answer 1

这不是好的做法，我很确定“我会因为帮助你而得到负面评价”，不管怎样，我只是按照你的要求做了。

Below Query using ROW_NUMBER will help you get what you need exactly.

CREATE TABLE #customer(Id INT PRIMARY KEY,Name VARCHAR(255))
CREATE TABLE #TransactionRecharge(TransactionId VARCHAR(255),CustomerId INT FOREIGN KEY REFERENCES #customer(id))

INSERT INTO #customer
VALUES (1,'Raj'),(2,'Bala'),(3,'Chandra')

INSERT INTO #TransactionRecharge
VALUES ('reansaction1',1),('reansaction2',1),
       ('reansaction3',1),('reansaction4',1),
       ('reansaction5',1),('reansaction6',1),
       ('reansaction7',1),('reansaction8',2)

SELECT  
    CASE 
        WHEN ROW_NUMBER() OVER ( PARTITION BY a.id ORDER BY b.TransactionId,a.Id) = '1' THEN CONVERT(VARCHAR,a.Id)
        ELSE ''
    END AS Customer,
    CASE
        WHEN ROW_NUMBER() OVER ( PARTITION BY a.id ORDER BY b.TransactionId,a.Id) = '1' THEN Name
        ELSE ''
    END AS Name,
    b.TransactionId  
FROM
    #TransactionRecharge b
LEFT JOIN 
    #customer a ON a.Id = b.CustomerId
WHERE 1 = 1
--AND   b.CustomerId = 1
DROP TABLE #customer
DROP TABLE #TransactionRecharge

获取数据 employee table with 1 id and multiple transaction id

fetch data employee table with 1 id and multiple transaction id

mysql

sql

sql-server

transactions