Java 中的十六进制转十进制

Question

我的错误在哪里？

The results are often 48 to high. For the 0 case i will add an If-statement. I want the stay with both loops if it is possible :)

public static int HexadecimalToDecimal(String hex1) {

        char hex[] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };

        int intCache = 0;
        int runner = 0;
        int help = 0;
        int number = 0;

        for (int i = hex1.length(); i > 0; i--) {


            while (hex1.charAt(i - 1) != hex[help]) {
                help++;
                number = hex[help];
            }
            intCache += number * (Math.pow(16, runner));
            runner++;
        }

        return intCache;

    }

Answer 1

当你运行

            number = hex[help];

number 被分配了字符值 ('0')，而不是数值 0。“0”的字符值为 48。

Java 中的十六进制转十进制

Hexadecimal to decimal in Java

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