c#找出regex匹配的位置并加粗

Question

我使用 C# 制作了一个 Win 10 通用应用程序

我想将这两个匹配项的整行加粗。

Run Run = new Run();
Paragraph Paragraph = new Paragraph();
//RichTextBlock = RTB

Run.Text = "D1 abc \n E1 \n F1 \n D1 def";
Paragraph.Inlines.Add(Run);
RTB.Blocks.Add(Paragraph);

string Patter = "D1";
Regex Regex = new Regex(Patter);
MatchCollection Mc = Regex.Matches(Run.Text);

foreach (Match Match in Mc)
{
        //bold the D1's lines in the RTB
}

输出：

**D1 abc**
E1
F1
**D1 def**

感谢您的帮助和时间

Answer 1

假设您的文本位于名为 text:

的变量中

string text = "D1 abc \n E1 \n F1 \n D1 def";


string Patter = "^.*D1.*$";
MatchCollection Mc = Regex.Matches(text, Patter, RegexOptions.Multiline);


int index = 0;

Paragraph.Inlines.Clear();

foreach (Match Match in Mc)
{
    //bold the D1's lines in the RTB
    Paragraph.Inlines.Add(new Run { Text = text.Substring(index, Match.Index - index) });

    var bold = new Bold();

    bold.Inlines.Add(new Run { Text = text.Substring(Match.Index, Match.Length) });

    Paragraph.Inlines.Add(bold);

    index = Match.Index + Match.Length;
}

if (index < text.Length)
{
    Paragraph.Inlines.Add(new Run { Text = text.Substring(index) });
}

基本上，我更改了正则表达式以匹配整行而不是仅匹配 "D1"。然后清空段落内容，根据匹配追加正文和粗体。

c#找出regex匹配的位置并加粗

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win-universal-app