如何在 spring 集成中从 Axis2 获取响应消息
how can I get the response message from Axis2 in spring integration
我需要在 spring 集成中集成我的网络服务 (Axis2):我有 spring-axis2-message.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/integration"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:stream="http://www.springframework.org/schema/integration/stream"
xmlns:ws="http://www.springframework.org/schema/integration/ws"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/integration
http://www.springframework.org/schema/integration/spring-integration.xsd
http://www.springframework.org/schema/integration/stream
http://www.springframework.org/schema/integration/stream/spring-integration-stream.xsd
http://www.springframework.org/schema/integration/ws
http://www.springframework.org/schema/integration/ws/spring-integration-ws.xsd">
<chain input-channel="messageChannelIN" output-channel="messageChannelOUT">
<ws:header-enricher >
<ws:soap-action value="getMessageService"/>
</ws:header-enricher>
<ws:outbound-gateway uri="http://localhost:8080/axis2-webservice/services/wservices?wsdl" reply-channel="messageChannelOUT"/>
</chain>
<!-- The response from the service is logged to the console. -->
<stream:stdout-channel-adapter id="messageChannelOUT" append-newline="true" />
</beans:beans>
还有一个TestAxis2.java
package org.neos.spring.test;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.integration.support.MessageBuilder;
import org.springframework.integration.support.channel.BeanFactoryChannelResolver;
import org.springframework.messaging.Message;
import org.springframework.messaging.MessageChannel;
import org.springframework.messaging.core.DestinationResolver;
public class TestAxis2 {
public static void main(String[] args) {
ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext(
"/META-INF/spring/integration/spring-axis2-message.xml");
DestinationResolver<MessageChannel> channelResolver = new BeanFactoryChannelResolver(context);
String requestXml =
"<getMessageService xmlns=\"http://service.ws.axis2.neos.org\">" +
"<name>HUGO</name>"
+ "</getMessageService>";
// Create the Message object
Message<String> message = MessageBuilder.withPayload(requestXml).build();
// Send the Message to the handler's input channel
MessageChannel channel = channelResolver.resolveDestination("messageChannelIN");
channel.send(message);
}
}
程序 运行 非常好,我可以在控制台中看到下一个响应:
<?xml version="1.0" encoding="UTF-8"?><ns:getMessageServiceResponse xmlns:ns="http://service.ws.axis2.neos.org"><ns:return>HELLO HUGO!, WELCOME TO WEBSERVICE AXIS1 hola</ns:return></ns:getMessageServiceResponse>
我的问题是 manipulate/How 如何才能在 Java 程序中得到响应,因为我需要响应。我尝试做很多事情,但不幸的是什么都没做我只能在控制台中看到响应,但我需要操纵响应。
我不知道如何访问此配置或是否需要配置其他内容。
access<stream:stdout-channel-adapter id="messageChannelOUT" append-newline="true" />
有人可以帮我吗?
使用一个Messaging Gateway。
public interface Gateway
String sendAndReceive(String out);
}
<int:gateway service-interface="foo.Gateway"
default-request-channel="messageChannelIN" />
从链中删除 output-channel
回复将通过网关返回给调用者
Gatweway gw = context.getBean(Gateway.class);
...
String reply = gw.sendAndReceive(requestXml);
这样做的额外好处是不会将您的应用程序暴露给消息传递基础结构。
它正在运行我的程序!!感谢您的帮助加里罗素!!!你的评论很有用。
最终代码为:
xml 配置
........
<chain input-channel="messageChannelIN">
<ws:header-enricher>
<ws:soap-action value="getMessageService"/>
</ws:header-enricher>
<ws:outbound-gateway uri="http://localhost:8080/axis2-webservice/services/wservices?wsdl" />
</chain>
<gateway id="messageChannelOUT" service-interface="org.neos.spring.ws.service.GatewayAxis" default-request-channel="messageChannelIN"/>
Java代码:
public interface GatewayAxis {
@Gateway
String sendAndReceive(String out);}
测试轴2
public static void main(String[] args) {
ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext(
"/META-INF/spring/integration/spring-axis2-message.xml");
GatewayAxis gateway = context.getBean(GatewayAxis.class);
String requestXml =
"<getMessageService xmlns=\"http://service.ws.axis2.neos.org\">" +
"<name>HUGO</name>"
+ "</getMessageService>";
String reply = gateway.sendAndReceive(requestXml);
System.out.println(reply);
}
我需要在 spring 集成中集成我的网络服务 (Axis2):我有 spring-axis2-message.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/integration"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:stream="http://www.springframework.org/schema/integration/stream"
xmlns:ws="http://www.springframework.org/schema/integration/ws"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/integration
http://www.springframework.org/schema/integration/spring-integration.xsd
http://www.springframework.org/schema/integration/stream
http://www.springframework.org/schema/integration/stream/spring-integration-stream.xsd
http://www.springframework.org/schema/integration/ws
http://www.springframework.org/schema/integration/ws/spring-integration-ws.xsd">
<chain input-channel="messageChannelIN" output-channel="messageChannelOUT">
<ws:header-enricher >
<ws:soap-action value="getMessageService"/>
</ws:header-enricher>
<ws:outbound-gateway uri="http://localhost:8080/axis2-webservice/services/wservices?wsdl" reply-channel="messageChannelOUT"/>
</chain>
<!-- The response from the service is logged to the console. -->
<stream:stdout-channel-adapter id="messageChannelOUT" append-newline="true" />
</beans:beans>
还有一个TestAxis2.java
package org.neos.spring.test;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.integration.support.MessageBuilder;
import org.springframework.integration.support.channel.BeanFactoryChannelResolver;
import org.springframework.messaging.Message;
import org.springframework.messaging.MessageChannel;
import org.springframework.messaging.core.DestinationResolver;
public class TestAxis2 {
public static void main(String[] args) {
ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext(
"/META-INF/spring/integration/spring-axis2-message.xml");
DestinationResolver<MessageChannel> channelResolver = new BeanFactoryChannelResolver(context);
String requestXml =
"<getMessageService xmlns=\"http://service.ws.axis2.neos.org\">" +
"<name>HUGO</name>"
+ "</getMessageService>";
// Create the Message object
Message<String> message = MessageBuilder.withPayload(requestXml).build();
// Send the Message to the handler's input channel
MessageChannel channel = channelResolver.resolveDestination("messageChannelIN");
channel.send(message);
}
}
程序 运行 非常好,我可以在控制台中看到下一个响应:
<?xml version="1.0" encoding="UTF-8"?><ns:getMessageServiceResponse xmlns:ns="http://service.ws.axis2.neos.org"><ns:return>HELLO HUGO!, WELCOME TO WEBSERVICE AXIS1 hola</ns:return></ns:getMessageServiceResponse>
我的问题是 manipulate/How 如何才能在 Java 程序中得到响应,因为我需要响应。我尝试做很多事情,但不幸的是什么都没做我只能在控制台中看到响应,但我需要操纵响应。
我不知道如何访问此配置或是否需要配置其他内容。
access<stream:stdout-channel-adapter id="messageChannelOUT" append-newline="true" />
有人可以帮我吗?
使用一个Messaging Gateway。
public interface Gateway String sendAndReceive(String out); } <int:gateway service-interface="foo.Gateway" default-request-channel="messageChannelIN" />
从链中删除
output-channel
回复将通过网关返回给调用者
Gatweway gw = context.getBean(Gateway.class); ... String reply = gw.sendAndReceive(requestXml);
这样做的额外好处是不会将您的应用程序暴露给消息传递基础结构。
它正在运行我的程序!!感谢您的帮助加里罗素!!!你的评论很有用。
最终代码为:
xml 配置
........
<chain input-channel="messageChannelIN">
<ws:header-enricher>
<ws:soap-action value="getMessageService"/>
</ws:header-enricher>
<ws:outbound-gateway uri="http://localhost:8080/axis2-webservice/services/wservices?wsdl" />
</chain>
<gateway id="messageChannelOUT" service-interface="org.neos.spring.ws.service.GatewayAxis" default-request-channel="messageChannelIN"/>
Java代码:
public interface GatewayAxis {
@Gateway
String sendAndReceive(String out);}
测试轴2
public static void main(String[] args) {
ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext(
"/META-INF/spring/integration/spring-axis2-message.xml");
GatewayAxis gateway = context.getBean(GatewayAxis.class);
String requestXml =
"<getMessageService xmlns=\"http://service.ws.axis2.neos.org\">" +
"<name>HUGO</name>"
+ "</getMessageService>";
String reply = gateway.sendAndReceive(requestXml);
System.out.println(reply);
}