jQuery 与单选按钮一起使用以确定下一步要转到的页面

jQuery used with Radio Buttons to Determine which page to go to next

我正在尝试在我的表单中使用 jQuery。 我为客户设置了单选按钮,可以作为客人结帐或注册帐户。我希望用户如果 select 'guest' 直接进入 shipping.php 页面,如果他们 select 'register'.

我根据 selected 使用了不同的函数,所以这在理论上应该可行,但我不确定为什么不行。

<div class="col-sm-offset-2 col-sm-4">
<form id="firstCheckout" method="post" action="shipping.php"><!--Add option of going to sign in page for creating an account if register is selected-->
    <div class="row">
        <h2>Sign In</h2>
    </div>
    <div class="row">
        <div class="form-group top-buffer col-sm-10">
                <input id="guest" type="radio" name="user" checked="checked" value="guest">
                <label for="guest">Checkout As Guest</label>
        </div>
    </div>
     <div class="row">
        <div class="form-group col-sm-10">
                <input id="register" type="radio" name="user" value="register">
                <label for="register">Register</label>
        </div>
    </div>
    <div class="row top-buffer">
        <button type="guest_submit" class="btn btn-default">Continue</button>
    </div>
</form>

<script>

    $(document).ready(function() {
        $(‘#guest’).click(function() {
            $(‘#firstCheckout’).attr(‘action’, ‘shipping.php’);
        });

        $(‘#register’).click(function() {
            $(‘#firstCheckout’).attr(‘action’, ‘register.php’);
        });
    });

</script>

它确实有效,我认为问题出在引用类型 您正在使用尝试 '"

更新:我猜是你的按钮类型不对,我已经把它改成submit并更新了代码。如果您仍然面临问题,那么我建议您在使用 Chrome 开发人员工具单击单选按钮后检查表单标签的操作。这应该可以帮助您进一步排除故障 :)

$(document).ready(function() {
  $('#guest').click(function() {
    alert('shipping.php');
    //$(‘#firstCheckout’).attr(‘action’, ‘shipping.php’);
  });

  $('#register').click(function() {
    alert('register.php');
    //$(‘#firstCheckout’).attr(‘action’, ‘register.php’);
  });
});
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css" integrity="sha512-dTfge/zgoMYpP7QbHy4gWMEGsbsdZeCXz7irItjcC3sPUFtf0kuFbDz/ixG7ArTxmDjLXDmezHubeNikyKGVyQ==" crossorigin="anonymous">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="col-sm-offset-2 col-sm-4">
  <form id="firstCheckout" method="post" action="shipping.php">
    <!--Add option of going to sign in page for creating an account if register is selected-->
    <div class="row">
      <h2>Sign In</h2>
    </div>
    <div class="row">
      <div class="form-group top-buffer col-sm-10">
        <input id="guest" type="radio" name="user" checked="checked" value="guest">
        <label for="guest">Checkout As Guest</label>
      </div>
    </div>
    <div class="row">
      <div class="form-group col-sm-10">
        <input id="register" type="radio" name="user" value="register">
        <label for="register">Register</label>
      </div>
    </div>
    <div class="row top-buffer">
      <button type="submit" class="btn btn-default">Continue</button>
    </div>
  </form>