大查询，如果重复记录（展平）

Question

这是关于以下问题的解决方案 BigQuery SQL IF over repeated record：我已经尝试创建一个测试 table 并尝试了给定的查询，但它实际上并没有选择生活的人在纽约和芝加哥。测试数据如下：

{"fullname": "John Smith", "citiesLived": [{"place": "newyork"}, {"place": "chicago"}, {"place": "seattle"}]}
{"fullname": "Adam Smith", "citiesLived": [{"place": "newyork"}, {"place": "chicago"}, {"place": "phil"}]}
{"fullname": "Adam Jefferson", "citiesLived": [{"place": "boston"}, {"place": "chicago"}, {"place": "seattle"}]}

查询如下：

SELECT
  *
FROM (
  SELECT
    fullname,
    IF (citiesLived.place == 'newyork', 1, 0) AS ny,
    IF (citiesLived.place == 'chicago', 1, 0) AS chi
  FROM (FLATTEN(tester.citiesLived, citiesLived))
  OMIT
    RECORD IF citiesLived.place = 'seattle')
WHERE
  ny == 1
  AND chi == 1

Answer 1

您不需要执行 FLATTEN（通常在 BigQuery 查询中很少需要 FLATTEN），只需 OMIT IF 就足够了：

SELECT fullname FROM tester.citiesLived
OMIT RECORD IF NOT (
  SOME(citiesLived.place = "newyork") AND
  SOME(citiesLived.place = "chicago"))

OMIT IF 的条件表明，如果居住的城市中有一些是纽约，一些是芝加哥 - 那么它符合您的条件。但是两者都不正确的记录 - 应该被省略（因此 NOT 谓词）。

Answer 2

我相信这将是对原始预期查询的更完整重写：

SELECT
  *
FROM (
  SELECT
    fullname,
    SOME(citiesLived.place == 'newyork') WITHIN RECORD AS ny,
    SOME(citiesLived.place == 'chicago') WITHIN RECORD AS chi
  FROM tester.citiesLived
  OMIT
    RECORD IF SOME(citiesLived.place = 'seattle'))
WHERE
  ny == true
  AND chi == true

大查询，如果重复记录（展平）

Big Query if over repeated record (with flatten)

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